anonymous
  • anonymous
A conveyor belt traveling at 3.0ms and at an angle of 20 to the horizontal has 18kg of sugar dropped on to it each second.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1350219671114:dw|
anonymous
  • anonymous
the force which the belt must exert on the sugar to accelerate it to the speed of the belt?
anonymous
  • anonymous
@Callisto @Coolsector @ParthKohli

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More answers

anonymous
  • anonymous
ill give you a hint .. the sugar momentum changes when i gets on the belt use F = dp/dt and find out the force that the belt exert's on the sugar
anonymous
  • anonymous
now how do we demonstrate this in the diagram, becoz the weight down the slope should also be considered..
anonymous
  • anonymous
i think we should add the weight (affective part due to the angle) to the dp/dt term
anonymous
  • anonymous
can u show these forces in a diagram?
anonymous
  • anonymous
@Vincent-Lyon.Fr
anonymous
  • anonymous
|dw:1350220276938:dw|
anonymous
  • anonymous
the dp/dt part acts for a short time
anonymous
  • anonymous
so where is force exerted on the sugar by belt?
anonymous
  • anonymous
dp/dt + mgx
anonymous
  • anonymous
the dp/dt is just to give it a speed of 3ms and the mgx is always there
anonymous
  • anonymous
no mgx is mgsin20
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
You need to consider total momentum before and after an elementary mass dm of sugar joins the conveyor belt.
anonymous
  • anonymous
dp/dt is 18 * 3
anonymous
  • anonymous
so you have 18 * 9.8 * sin(20) + 18 * 3 = 114.33
anonymous
  • anonymous
cool sector, i just need a system showing all this forces so tht i can resolve each of them and find force? is i possible?
anonymous
  • anonymous
this is the system that shows the forces on the sugar at the moment it touches the belt!
anonymous
  • anonymous
okay il do it thanks :)
anonymous
  • anonymous
you can give the dp/dt a different name maybe it will look better for you.. the thing to understand is that at the moment of touch the belt exerts dp/dt + mgx on the sugar

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