A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
A conveyor belt traveling at 3.0ms and at an angle of 20 to the horizontal has 18kg of sugar dropped on to it each second.
anonymous
 4 years ago
A conveyor belt traveling at 3.0ms and at an angle of 20 to the horizontal has 18kg of sugar dropped on to it each second.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350219671114:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the force which the belt must exert on the sugar to accelerate it to the speed of the belt?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Callisto @Coolsector @ParthKohli

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ill give you a hint .. the sugar momentum changes when i gets on the belt use F = dp/dt and find out the force that the belt exert's on the sugar

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now how do we demonstrate this in the diagram, becoz the weight down the slope should also be considered..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think we should add the weight (affective part due to the angle) to the dp/dt term

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u show these forces in a diagram?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350220276938:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the dp/dt part acts for a short time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so where is force exerted on the sugar by belt?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the dp/dt is just to give it a speed of 3ms and the mgx is always there

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You need to consider total momentum before and after an elementary mass dm of sugar joins the conveyor belt.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so you have 18 * 9.8 * sin(20) + 18 * 3 = 114.33

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cool sector, i just need a system showing all this forces so tht i can resolve each of them and find force? is i possible?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is the system that shows the forces on the sugar at the moment it touches the belt!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay il do it thanks :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can give the dp/dt a different name maybe it will look better for you.. the thing to understand is that at the moment of touch the belt exerts dp/dt + mgx on the sugar
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.