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anonymous
 4 years ago
A conveyor belt traveling at 3.0ms and at an angle of 20 to the horizontal has 18kg of sugar dropped on to it each second.
anonymous
 4 years ago
A conveyor belt traveling at 3.0ms and at an angle of 20 to the horizontal has 18kg of sugar dropped on to it each second.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350219671114:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the force which the belt must exert on the sugar to accelerate it to the speed of the belt?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Callisto @Coolsector @ParthKohli

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ill give you a hint .. the sugar momentum changes when i gets on the belt use F = dp/dt and find out the force that the belt exert's on the sugar

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now how do we demonstrate this in the diagram, becoz the weight down the slope should also be considered..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think we should add the weight (affective part due to the angle) to the dp/dt term

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u show these forces in a diagram?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350220276938:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the dp/dt part acts for a short time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so where is force exerted on the sugar by belt?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the dp/dt is just to give it a speed of 3ms and the mgx is always there

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0You need to consider total momentum before and after an elementary mass dm of sugar joins the conveyor belt.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so you have 18 * 9.8 * sin(20) + 18 * 3 = 114.33

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cool sector, i just need a system showing all this forces so tht i can resolve each of them and find force? is i possible?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is the system that shows the forces on the sugar at the moment it touches the belt!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay il do it thanks :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can give the dp/dt a different name maybe it will look better for you.. the thing to understand is that at the moment of touch the belt exerts dp/dt + mgx on the sugar
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