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experimentX
 4 years ago
Q
experimentX
 4 years ago
Q

This Question is Closed

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350223048970:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350223094711:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350223141650:dwdw:1350223162295:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hmm.. So.. *strength* < how to calculate that??

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1in case of platform dw:1350223305158:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350223350144:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What about the platform? Something ugly is that the platform is something you need to balance but it also provides support to you!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350223607516:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1assuming that case II in not our case.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350223731501:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350223745248:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350224941551:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why is the tension opposite?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1think of this in this way ... suppose platform is broken ... dw:1350225254972:dw how do you balance this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0T1 + T2 = W1+W2 F = T2 Hmm, probably it's wrong.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yes that that's right ... dw:1350225421414:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Huh?! Seriously?! That's..... *right* ?!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yep ... but your are seeking more trouble!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How can I reduce those trouble if they are really that troublesome :

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1... well ... if you take up trouble then you will understand more. give it a try.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0T1 + T2 = W1+W2 F = T2 So, T1 + F = W1 + W2 For max F, F = W1 And .. it cancels out... T1 = W2 What's wrong with me!!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1suppose ... the weight of platform is less than weight of person.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1I'll give you simple Q.dw:1350226233525:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.010N  5N = 5N (downwards)?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yep ... you have to apply the same case here. The person is pulling the string down < the person is being pulled up you need to split the weight of person.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0FT1 ? That looks strange!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350226496018:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1both tension and weight is a force ... so you can add them up.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350226590287:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1350228019586:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350228159702:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1sorry ... I forgot to highlight it .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's my mistake. I'm just too stupid! Sorry!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1partly my fault too ... I don't elaborate ... usually use figures ... so I should have highlighted.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1what is the max force that you can apply ... refer to the first post!!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1so you havedw:1350228670243:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yep ... that's correct ... we arrived at the conclusion what we did without any trouble.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Trouble trouble trouble!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1well ... I hope you understood it better.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If I don't understand ... I will ask!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1sure ... sometimes troubles are worth taking. It gives insight on problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Only if I know that ''insight''..
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