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Hmm.. So.. *strength* <- how to calculate that??
in case of platform |dw:1350223305158:dw|
What about the platform? Something ugly is that the platform is something you need to balance but it also provides support to you!
assuming that case II in not our case.
Why is the tension opposite?
think of this in this way ... suppose platform is broken ... |dw:1350225254972:dw| how do you balance this?
T1 + T2 = W1+W2 F = T2 Hmm, probably it's wrong.
yes that that's right ... |dw:1350225421414:dw|
Huh?! Seriously?! That's..... *right* ?!
yep ... but your are seeking more trouble!!
How can I reduce those trouble if they are really that troublesome :|
... well ... if you take up trouble then you will understand more. give it a try.
T1 + T2 = W1+W2 F = T2 So, T1 + F = W1 + W2 For max F, F = W1 And .. it cancels out... T1 = W2 What's wrong with me!!
suppose ... the weight of platform is less than weight of person.
I'll give you simple Q.|dw:1350226233525:dw|
10N - 5N = 5N (downwards)?
yep ... you have to apply the same case here. The person is pulling the string down <-- the person is being pulled up you need to split the weight of person.
F-T1 ? That looks strange!
both tension and weight is a force ... so you can add them up.
sorry ... I forgot to highlight it .
It's my mistake. I'm just too stupid! Sorry!
partly my fault too ... I don't elaborate ... usually use figures ... so I should have highlighted.
so do you get it?
what is the max force that you can apply ... refer to the first post!!
so you have|dw:1350228670243:dw|
yep ... that's correct ... we arrived at the conclusion what we did without any trouble.
Trouble trouble trouble!
well ... I hope you understood it better.
If I don't understand ... I will ask!
sure ... sometimes troubles are worth taking. It gives insight on problem.
Only if I know that ''insight''..