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experimentX

  • 2 years ago

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  1. experimentX
    • 2 years ago
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    |dw:1350223048970:dw|

  2. experimentX
    • 2 years ago
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    |dw:1350223094711:dw|

  3. experimentX
    • 2 years ago
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    |dw:1350223141650:dw||dw:1350223162295:dw|

  4. RolyPoly
    • 2 years ago
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    Hmm.. So.. *strength* <- how to calculate that??

  5. experimentX
    • 2 years ago
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    in case of platform |dw:1350223305158:dw|

  6. experimentX
    • 2 years ago
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    |dw:1350223350144:dw|

  7. RolyPoly
    • 2 years ago
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    What about the platform? Something ugly is that the platform is something you need to balance but it also provides support to you!

  8. experimentX
    • 2 years ago
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    |dw:1350223607516:dw|

  9. experimentX
    • 2 years ago
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    assuming that case II in not our case.

  10. experimentX
    • 2 years ago
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    |dw:1350223731501:dw|

  11. RolyPoly
    • 2 years ago
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    |dw:1350223745248:dw|

  12. experimentX
    • 2 years ago
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    |dw:1350224941551:dw|

  13. RolyPoly
    • 2 years ago
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    Why is the tension opposite?

  14. experimentX
    • 2 years ago
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    think of this in this way ... suppose platform is broken ... |dw:1350225254972:dw| how do you balance this?

  15. RolyPoly
    • 2 years ago
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    T1 + T2 = W1+W2 F = T2 Hmm, probably it's wrong.

  16. experimentX
    • 2 years ago
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    yes that that's right ... |dw:1350225421414:dw|

  17. RolyPoly
    • 2 years ago
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    Huh?! Seriously?! That's..... *right* ?!

  18. experimentX
    • 2 years ago
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    yep ... but your are seeking more trouble!!

  19. RolyPoly
    • 2 years ago
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    How can I reduce those trouble if they are really that troublesome :|

  20. experimentX
    • 2 years ago
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    ... well ... if you take up trouble then you will understand more. give it a try.

  21. RolyPoly
    • 2 years ago
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    T1 + T2 = W1+W2 F = T2 So, T1 + F = W1 + W2 For max F, F = W1 And .. it cancels out... T1 = W2 What's wrong with me!!

  22. experimentX
    • 2 years ago
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    suppose ... the weight of platform is less than weight of person.

  23. experimentX
    • 2 years ago
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    I'll give you simple Q.|dw:1350226233525:dw|

  24. RolyPoly
    • 2 years ago
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    10N - 5N = 5N (downwards)?

  25. experimentX
    • 2 years ago
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    yep ... you have to apply the same case here. The person is pulling the string down <-- the person is being pulled up you need to split the weight of person.

  26. RolyPoly
    • 2 years ago
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    F-T1 ? That looks strange!

  27. experimentX
    • 2 years ago
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    |dw:1350226496018:dw|

  28. experimentX
    • 2 years ago
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    both tension and weight is a force ... so you can add them up.

  29. experimentX
    • 2 years ago
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    |dw:1350226590287:dw|

  30. experimentX
    • 2 years ago
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    |dw:1350228019586:dw|

  31. RolyPoly
    • 2 years ago
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    |dw:1350228159702:dw|

  32. experimentX
    • 2 years ago
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    sorry ... I forgot to highlight it .

  33. RolyPoly
    • 2 years ago
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    It's my mistake. I'm just too stupid! Sorry!

  34. experimentX
    • 2 years ago
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    partly my fault too ... I don't elaborate ... usually use figures ... so I should have highlighted.

  35. experimentX
    • 2 years ago
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    so do you get it?

  36. RolyPoly
    • 2 years ago
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    98%

  37. experimentX
    • 2 years ago
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    what is the max force that you can apply ... refer to the first post!!

  38. RolyPoly
    • 2 years ago
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    Your weight!

  39. experimentX
    • 2 years ago
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    so you have|dw:1350228670243:dw|

  40. RolyPoly
    • 2 years ago
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    W1

  41. experimentX
    • 2 years ago
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    yep ... that's correct ... we arrived at the conclusion what we did without any trouble.

  42. RolyPoly
    • 2 years ago
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    Trouble trouble trouble!

  43. experimentX
    • 2 years ago
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    well ... I hope you understood it better.

  44. RolyPoly
    • 2 years ago
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    If I don't understand ... I will ask!

  45. experimentX
    • 2 years ago
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    sure ... sometimes troubles are worth taking. It gives insight on problem.

  46. RolyPoly
    • 2 years ago
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    Only if I know that ''insight''..

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