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Tati_Lee
Group Title
What are the possible number of positive, negative, and complex zeros of f(x) = –x6 – x5– x4 – 4x3 – 12x2 + 12 ?
 one year ago
 one year ago
Tati_Lee Group Title
What are the possible number of positive, negative, and complex zeros of f(x) = –x6 – x5– x4 – 4x3 – 12x2 + 12 ?
 one year ago
 one year ago

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Tati_Lee Group TitleBest ResponseYou've already chosen the best response.1
Positive: 4, 2, or 0; Negative: 2 or 0; Complex: 6, 4, 2, or 0 Positive: 3 or 1; Negative: 3 or 1; Complex: 4, 2, or 0 Positive: 3 or 1; Negative: 2 or 0; Complex: 4, 2, or 0 Positive: 1; Negative: 5, 3, or 1; Complex: 4, 2, or 0
 one year ago

evergirl Group TitleBest ResponseYou've already chosen the best response.1
there are 1 or 3 negative real roots. So there are 4 or 2 complex roots.
 one year ago

evergirl Group TitleBest ResponseYou've already chosen the best response.1
is that what your looking for Tati?
 one year ago

Tati_Lee Group TitleBest ResponseYou've already chosen the best response.1
Yea Can you show me how you got it? I gotta do my DBA on the questions i got wrong on my exam review _
 one year ago

evergirl Group TitleBest ResponseYou've already chosen the best response.1
hold on....
 one year ago

evergirl Group TitleBest ResponseYou've already chosen the best response.1
I learned that "This is a polynomial of order 6, so there are 6 roots, so there is only one sign change for the coefficients, so there is exactly 1 positive real root. there are 3 sign changes, so there are at most 3 negative real roots." And that's how I got the answer....not sure if that makes any sense..
 one year ago

evergirl Group TitleBest ResponseYou've already chosen the best response.1
to you...
 one year ago

Tati_Lee Group TitleBest ResponseYou've already chosen the best response.1
yes it does.. thank you!
 one year ago

evergirl Group TitleBest ResponseYou've already chosen the best response.1
Your welcome!
 one year ago
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