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1/3y + 1/4 =5/12

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do i simplfy ?
you would need common denominators, before you do anything. Do you know how to do that? I can walk you through it if you're not familiar with that

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Other answers:

yea one min
almost So it's \[\frac{4}{12}y+\frac{3}{12}=\frac{5}{12}\] because \[\frac44\cdot \frac{1}{3}y+\frac33 \cdot \frac{1}{4}=\frac{5}{12}\]
does that make sense?
so 5/12 stays the same ?
yes because it already has the common denominator of 12. We're trying to make it so that all the numbers have 12 on the bottom
now we can solve for y
ok im re writing it
i got stuck
\[\frac{4}{12}y+\frac{3}{12}=\frac{5}{12}\] ok now we need to get \[\frac3{12}\] over to the right hand side of the equal sign so subtract \[\frac3{12}\] from both sides \[\frac{4}{12}y+\cancel{\frac{3}{12}-\frac3{12}}=\frac{5}{12}-\frac3{12}\]
4/12y =2/12
now we need to get the y out of the denominator. do you know how to do that?
multiply ?
wait, is y in the denominator or is it just like this: \[\frac4{12}y =\frac2{12}\]
was this the original equation? \[\frac{4}{12}y+\frac{3}{12}=\frac{5}{12}\] or this \[\frac{4}{12y}+\frac{3}{12}=\frac{5}{12}\] ?
the 1st one
sorry i've been mistyping let's try that again LOL
\[\frac{4}{12}y=\frac{2}{12}\] now we can multiply both sides by \[\frac{12}1\] to get rid of the 12 in the denominator because we don't need it anymore. It makes it easier to solve for y this way so \[\frac{12}1 \cdot \frac{4}{12}y=\frac{12}1 \cdot \frac{2}{12}\]
is it 2 ? :D
almost so we're left with 4y=2 so what does y=?
2 .....
:( i was close
because we have to divide by 4 to get y by itself
Yep you were almost there! so now you just need to simplify \[\frac24\]
ohhh ok lol
\[y=\frac12\] very good!

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