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rawrrainbowsz2 Group Title

1/3y + 1/4 =5/12

  • 2 years ago
  • 2 years ago

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  1. rawrrainbowsz2 Group Title
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    |dw:1350228174103:dw|

    • 2 years ago
  2. rawrrainbowsz2 Group Title
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    do i simplfy ?

    • 2 years ago
  3. JenniferSmart1 Group Title
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    you would need common denominators, before you do anything. Do you know how to do that? I can walk you through it if you're not familiar with that

    • 2 years ago
  4. rawrrainbowsz2 Group Title
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    yea one min

    • 2 years ago
  5. rawrrainbowsz2 Group Title
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    |dw:1350228511155:dw|

    • 2 years ago
  6. JenniferSmart1 Group Title
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    almost So it's \[\frac{4}{12}y+\frac{3}{12}=\frac{5}{12}\] because \[\frac44\cdot \frac{1}{3}y+\frac33 \cdot \frac{1}{4}=\frac{5}{12}\]

    • 2 years ago
  7. JenniferSmart1 Group Title
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    does that make sense?

    • 2 years ago
  8. rawrrainbowsz2 Group Title
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    so 5/12 stays the same ?

    • 2 years ago
  9. JenniferSmart1 Group Title
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    yes because it already has the common denominator of 12. We're trying to make it so that all the numbers have 12 on the bottom

    • 2 years ago
  10. JenniferSmart1 Group Title
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    now we can solve for y

    • 2 years ago
  11. rawrrainbowsz2 Group Title
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    ok im re writing it

    • 2 years ago
  12. rawrrainbowsz2 Group Title
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    |dw:1350228980674:dw|

    • 2 years ago
  13. rawrrainbowsz2 Group Title
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    i got stuck

    • 2 years ago
  14. JenniferSmart1 Group Title
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    \[\frac{4}{12}y+\frac{3}{12}=\frac{5}{12}\] ok now we need to get \[\frac3{12}\] over to the right hand side of the equal sign so subtract \[\frac3{12}\] from both sides \[\frac{4}{12}y+\cancel{\frac{3}{12}-\frac3{12}}=\frac{5}{12}-\frac3{12}\]

    • 2 years ago
  15. rawrrainbowsz2 Group Title
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    4/12y =2/12

    • 2 years ago
  16. JenniferSmart1 Group Title
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    yes!

    • 2 years ago
  17. JenniferSmart1 Group Title
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    now we need to get the y out of the denominator. do you know how to do that?

    • 2 years ago
  18. rawrrainbowsz2 Group Title
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    multiply ?

    • 2 years ago
  19. JenniferSmart1 Group Title
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    wait, is y in the denominator or is it just like this: \[\frac4{12}y =\frac2{12}\]

    • 2 years ago
  20. JenniferSmart1 Group Title
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    was this the original equation? \[\frac{4}{12}y+\frac{3}{12}=\frac{5}{12}\] or this \[\frac{4}{12y}+\frac{3}{12}=\frac{5}{12}\] ?

    • 2 years ago
  21. rawrrainbowsz2 Group Title
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    the 1st one

    • 2 years ago
  22. JenniferSmart1 Group Title
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    sorry i've been mistyping let's try that again LOL

    • 2 years ago
  23. JenniferSmart1 Group Title
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    \[\frac{4}{12}y=\frac{2}{12}\] now we can multiply both sides by \[\frac{12}1\] to get rid of the 12 in the denominator because we don't need it anymore. It makes it easier to solve for y this way so \[\frac{12}1 \cdot \frac{4}{12}y=\frac{12}1 \cdot \frac{2}{12}\]

    • 2 years ago
  24. rawrrainbowsz2 Group Title
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    is it 2 ? :D

    • 2 years ago
  25. JenniferSmart1 Group Title
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    almost so we're left with 4y=2 so what does y=?

    • 2 years ago
  26. rawrrainbowsz2 Group Title
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    2 .....

    • 2 years ago
  27. JenniferSmart1 Group Title
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    \[y=\frac24\]

    • 2 years ago
  28. rawrrainbowsz2 Group Title
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    :( i was close

    • 2 years ago
  29. JenniferSmart1 Group Title
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    because we have to divide by 4 to get y by itself

    • 2 years ago
  30. JenniferSmart1 Group Title
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    Yep you were almost there! so now you just need to simplify \[\frac24\]

    • 2 years ago
  31. rawrrainbowsz2 Group Title
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    ohhh ok lol

    • 2 years ago
  32. rawrrainbowsz2 Group Title
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    1/2

    • 2 years ago
  33. JenniferSmart1 Group Title
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    \[y=\frac12\] very good!

    • 2 years ago
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