## benzo 2 years ago h5p2.....im lost on this....give me step by step how you do this please....What is the minimum value of VDD (in Volts) that we must supply to keep the transistor in the region of saturated operation?

1. thoppa

what are ur values given.............give the cumplete question

2. thoppa

dude answer something between 2 to 7

3. thoppa

try it

4. thoppa

i guess you got it

5. benzo

not yet

6. muhammedvaseem007

vdd=5.5. just try it

7. benzo

i got it...VIN-VOUT greater or equall ti VT...VT=2.0 6.1-3.6=2.5 5.4-2.9=2.5 6.8-4.2=2.6 VIN-VT 6.8-2=4.8 VDD=4.8

8. muhammedvaseem007

is you check. i though it must be corect

9. muhammedvaseem007

vdd is 5.5 for me. other vin is diferent

10. benzo

ok right for me....thanks.....H5P1.....whats the step by step solution 1, 2, 3

11. muhammedvaseem007

12. benzo

step by step solution

13. muhammedvaseem007

, we have to find max Vin ; to find Vin let us apply kvll to the input loop Vin - Vgs+1 =0; ie, Vin = Vgs-1 ...............................(eqn1) now the unknown parameter is Vgs, hence to find it lets apply KVL to external loop : 1-Ids*R-Vds+1=0 , further substituting the value of Ids = k/2 *(Vgs-Vt)^2 in the above equation and solving the quadratic equation we will get, Vds = 0.593, -0.84 : as Vds needs tobe +ve hence neglecting he -ve term we have Vds = 0.593 and we know Vds = Vgs-Vt ie Vgs = Vds+Vt therefore, Vgs = 0.593+0.5=1.093 and substituting the above valuw in eqn1 we have Vin=1.093-1=0.093

14. akash97

@benzo : In saturation: iDS=K/2*(vGS-VT)2, and since here vGS is vIN-vOUT, then iDS=K/2*(vIN-vOUT-VT)2 Q2 vOUT=

15. akash97

vOUT=iDS*RS

16. benzo

thanks lab and hw 100%

17. muhammedvaseem007

i get the vout for sorce flower small signal but its doesn't work what you vout for source flower small signal

18. Coolamigo

vi=0.0009V what is the incremental output vo? also Gain

19. muhammedvaseem007

gain=0.9498

20. Coolamigo

and vo?

21. muhammedvaseem007

yes vo=0.9498

22. Coolamigo

Wont that conclude a gain of 1055?

23. Coolamigo

Bro Gain is .94 vo=?

24. ali110

Q1 vOUT = iDS*RS vout/vin = ϑvOUT/ϑvIN @ VIN = RS * ϑiDS/ϑvIN = RS * (1/RS + 1/(K*RS 2)*(-2K*RS/(2d)) where d=sqrt(1+2K*RS*(VIN-VT))) Simplifying the expression above will give: vout/vin = (1-1/d) à vout=vin*(1-1/sqrt(1+2K*RS*(VIN-VT)))) Q2 For K=2 [A/V2], VT=2V, RS=16Ω, VIN=6.5V and vin=0.001 V, d=19.925 and thus vout/vin = (1-1/d) à vout=0.001*(1-1/19.925)=0.001*0.9498 à vout = 0.0009498 V Q3 We've already found voltage gain solving for Q2. vout/vin = (1-1/d) = 1-1/19.925 = 0.9498 You can see that source follower has a voltage gain slightly less than 1.

25. Coolamigo

vo= 0.0009498 gives X (wrong)

26. muhammedvaseem007