Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
estudier
Group Title
Circles, tangent everywhere, all the way up the triangle.
Sum of perimeters of all the triangles
(Bit difficult to draw this, wait a minute)
 2 years ago
 2 years ago
estudier Group Title
Circles, tangent everywhere, all the way up the triangle. Sum of perimeters of all the triangles (Bit difficult to draw this, wait a minute)
 2 years ago
 2 years ago

This Question is Closed

estudier Group TitleBest ResponseYou've already chosen the best response.0
dw:1350233869190:dw
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Base 20, and sides 26
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Sum of perimeters of all the circles, I mean...
 2 years ago

yomamabf Group TitleBest ResponseYou've already chosen the best response.0
wait r u trying to teach or is this something you really need help on? cuz ur at level 99
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Think of it as a tutorial (or not):)
 2 years ago

yomamabf Group TitleBest ResponseYou've already chosen the best response.0
so circles dont matter so i would add 20 to 26?
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
I already corrected that above, it is the perimeter of all the circles
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Hint This is just Pythagorus and a splash of imagination....
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
dw:1350234945917:dw is something missing ... like side of triangle or ... radius of circle of first and second??
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Maybe you didn't see it, sorry.. I posted above "Base 20, and sides 26"
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Maybe I should close it and repost it with out the error and including the figures :(
 2 years ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.3
No. I will solve it.
 2 years ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.3
Do you have an answer?
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Wow, this a lot of typing....
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Anyone just want to write out the infinite sum...?
 2 years ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.3
Try to check my solution. Lets sign the radiuses of the circles \(r_1, r_2,...\). Then their length will be \(2\pi r_1+2\pi r_2+...=2\pi(r_1+r_2+...)\). Now watch the picture.dw:1350235644893:dwFrom the picture you can see that radiuses take a half of the height of the triangle. So I conclude that the whole perimeter of the circumferences is \(\frac 12\cdot\sqrt{26^210^2}=12\)
 2 years ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.3
Sorry, forgot to multiply by \(2\pi\). Answer is \(24\pi\).
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
That's right, pi*(d1 + d2 +.....) = pi * altitude of triangle
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
I think I've seen this done before using a geometric progression.
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
@CliffSedge Yup, u could do that, lot more work though....
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Right, I will close this one....
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.