Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

estudier

  • 3 years ago

f(n) = integer nearest sqrt(n) 1/f(1) + 1/f(2) + ...........+1/f(9999) +1/f(10000) = ?

  • This Question is Closed
  1. mahmit2012
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350239055071:dw|

  2. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    That looks promising...

  3. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    So when is f(n) = m?

  4. experimentX
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    *

  5. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Get rid of them nasty radicals as well.....

  6. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    f(n) would range from 1 to 100

  7. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how to get rid of radical

  8. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    f(n) = a when (a-1/2)^2 < n < (a+1/2)^2 (I'm using a)

  9. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok

  10. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Think I will leave this one up overnight in case people want to think more about it....

  11. mukushla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and im watching :)

  12. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    does this involve integrals ?

  13. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Certainly not! (I'm not that fond of calculus)

  14. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    2a is the window for n until a increments

  15. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    is this right direction

  16. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes! Now u have the pattern, away u go....:-)

  17. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so f(n) = a a = 1 ; 2.1 times a = 2 ; 2.2 times .... a = 99; 2.99 times a = 100; 2.100/2 times

  18. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Then the sum is ?

  19. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The last bit is just some counting (don't overcount)

  20. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    lol its easy

  21. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    2a.1/a a would cancel out ! 99*2 + 1 = 199

  22. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes, well done...

  23. sara12345
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    nice exercise thnk you :)

  24. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yw

  25. estudier
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Since it has been solved I will close it after all....

  26. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy