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A wet bar of soap (m= 0.150 kg) slides down a ramp 2.0m long at an angle of 7.3 degrees. How long does it take to reach the bottom?
 one year ago
 one year ago
A wet bar of soap (m= 0.150 kg) slides down a ramp 2.0m long at an angle of 7.3 degrees. How long does it take to reach the bottom?
 one year ago
 one year ago

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TagujaBest ResponseYou've already chosen the best response.2
Since it is a wet bar of soap, I assume there is no friction. If we draw the forces diagram, we found that there is a resultant force of the normal reaction N and the gravitational force F=mg and that F=mgsin(alpha). That force is equal to F=ma, therefore mgsin(alpha)=ma=>a=gsin(alpha). From the equation t=sqrt(2x/a), we get that t is approximately 1,8 seconds. Keep in mind that this is actually independent of the mass of the body.
 one year ago

joshiBest ResponseYou've already chosen the best response.0
ohhhh i did F=mgcos. could you explain why it's sin? also thanks
 one year ago

joshiBest ResponseYou've already chosen the best response.0
no the answer is infact 1.8 ...
 one year ago

TagujaBest ResponseYou've already chosen the best response.2
Oh yeah.. Now i forgot taking the square root LOL... 1,8 seconds is infact the right answer. I hope that this sketch helps you :P
 one year ago

joshiBest ResponseYou've already chosen the best response.0
ohhh i see, i calculated a y component for gravity as well which doesn't really exist in this case. well anyway, thanks! :)
 one year ago
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