Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

joshi

  • 3 years ago

A wet bar of soap (m= 0.150 kg) slides down a ramp 2.0m long at an angle of 7.3 degrees. How long does it take to reach the bottom?

  • This Question is Closed
  1. Taguja
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Since it is a wet bar of soap, I assume there is no friction. If we draw the forces diagram, we found that there is a resultant force of the normal reaction N and the gravitational force F=mg and that F=mgsin(alpha). That force is equal to F=ma, therefore mgsin(alpha)=ma=>a=gsin(alpha). From the equation t=sqrt(2x/a), we get that t is approximately 1,8 seconds. Keep in mind that this is actually independent of the mass of the body.

  2. joshi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohhhh i did F=mgcos. could you explain why it's sin? also thanks

  3. joshi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no the answer is infact 1.8 ...

  4. Taguja
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Oh yeah.. Now i forgot taking the square root LOL... 1,8 seconds is infact the right answer. I hope that this sketch helps you :P

    1 Attachment
  5. joshi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohhh i see, i calculated a y component for gravity as well which doesn't really exist in this case. well anyway, thanks! :)

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy