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JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
let's start with \[\sqrt9\] what does that equal?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
make a guess
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
perfect!
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
\[3\cdot3+x=15\]
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
what is 3 times 3?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
ok so we now have \[9+x=15\] how do we get the 9 to the other side of the equal sign?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
make a guess
 one year ago

wabbit1993 Group TitleBest ResponseYou've already chosen the best response.1
i really don't know :/ i have been out of math for 3 years now. :(
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
no problem
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
we would subtract 9 from both sides to get x by itself so \[\cancel{99}+x=159\]
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
Yes! Good job!
 one year ago

wabbit1993 Group TitleBest ResponseYou've already chosen the best response.1
THANK YOUUUU!!!!
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
x=6
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
medal please? =D
 one year ago

wabbit1993 Group TitleBest ResponseYou've already chosen the best response.1
did i do the medal right?? I've never used this site before lol
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
I got it. Thank you!
 one year ago

wabbit1993 Group TitleBest ResponseYou've already chosen the best response.1
you're welcome. thank you so much as well!!
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
Glad to help!
 one year ago
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