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JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
let's start with \[\sqrt9\] what does that equal?
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
make a guess
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
perfect!
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
\[3\cdot3+x=15\]
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
what is 3 times 3?
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
ok so we now have \[9+x=15\] how do we get the 9 to the other side of the equal sign?
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
make a guess
 2 years ago

wabbit1993 Group TitleBest ResponseYou've already chosen the best response.1
i really don't know :/ i have been out of math for 3 years now. :(
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
no problem
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
we would subtract 9 from both sides to get x by itself so \[\cancel{99}+x=159\]
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
Yes! Good job!
 2 years ago

wabbit1993 Group TitleBest ResponseYou've already chosen the best response.1
THANK YOUUUU!!!!
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
medal please? =D
 2 years ago

wabbit1993 Group TitleBest ResponseYou've already chosen the best response.1
did i do the medal right?? I've never used this site before lol
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
I got it. Thank you!
 2 years ago

wabbit1993 Group TitleBest ResponseYou've already chosen the best response.1
you're welcome. thank you so much as well!!
 2 years ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.1
Glad to help!
 2 years ago
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