dddan
please help;
what is the equation of a line with the given points are (4,-1), (-2,-6)
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amorfide
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to get the equation of a line you do
y-y1=m(x-x1)
y1 is a y coordinate
x1 is an x coordinate
amorfide
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to get the gradient
|dw:1350247890237:dw|
amorfide
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y2 and y1 being the y coordinates
x2 and x1 being the x coordinates
jayz657
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find slope first (y1-y2) / (x1-x2)
so it is (-6 - (-1)) / (-2 - 4) = 5/6
y = mx + b
y= 5/6x + b
-1 = 5/6(4) + b
solvve for b
b = -26/6
eq: y= 5/6x -26/6
dddan
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alright i did that and got y=-7/6 x + 11/3
dddan
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to jayz657, i think its y2-y1/x2-x1..... to find slope right?
jayz657
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doesnt matter you get slope either way
y1 and y2 is to show these are 2 different numbers at 2 different points
dddan
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aight
dddan
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shount it be -5/6
jayz657
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its positive for me check your signs
dddan
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|dw:1350248542689:dw|
jayz657
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-5 / -6 is 5/6