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dddan Group Title

please help; what is the equation of a line with the given points are (4,-1), (-2,-6)

  • 2 years ago
  • 2 years ago

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  1. amorfide Group Title
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    to get the equation of a line you do y-y1=m(x-x1) y1 is a y coordinate x1 is an x coordinate

    • 2 years ago
  2. amorfide Group Title
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    to get the gradient |dw:1350247890237:dw|

    • 2 years ago
  3. amorfide Group Title
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    y2 and y1 being the y coordinates x2 and x1 being the x coordinates

    • 2 years ago
  4. jayz657 Group Title
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    find slope first (y1-y2) / (x1-x2) so it is (-6 - (-1)) / (-2 - 4) = 5/6 y = mx + b y= 5/6x + b -1 = 5/6(4) + b solvve for b b = -26/6 eq: y= 5/6x -26/6

    • 2 years ago
  5. dddan Group Title
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    alright i did that and got y=-7/6 x + 11/3

    • 2 years ago
  6. dddan Group Title
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    to jayz657, i think its y2-y1/x2-x1..... to find slope right?

    • 2 years ago
  7. jayz657 Group Title
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    doesnt matter you get slope either way y1 and y2 is to show these are 2 different numbers at 2 different points

    • 2 years ago
  8. dddan Group Title
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    aight

    • 2 years ago
  9. dddan Group Title
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    shount it be -5/6

    • 2 years ago
  10. jayz657 Group Title
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    its positive for me check your signs

    • 2 years ago
  11. dddan Group Title
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    |dw:1350248542689:dw|

    • 2 years ago
  12. jayz657 Group Title
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    -5 / -6 is 5/6

    • 2 years ago
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