baldymcgee6
  • baldymcgee6
Is taking the derivative of e^x technically using the exponential rule?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
derivative of e^x is e^x, it doesnt change not power rule if thats what you mean
baldymcgee6
  • baldymcgee6
I know what the derivative of e^x is, that's not what I asked.
anonymous
  • anonymous
theres no such thing as an exponetial rule btw

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baldymcgee6
  • baldymcgee6
@jayz657 http://en.wikipedia.org/wiki/Differentiation_rules#Derivatives_of_exponential_and_logarithmic_functions
anonymous
  • anonymous
that link shows derivatives of exponential functions there is no rule for it, all you need to know about derivatives of e^x is e^x or if your talk about functions like 2^x then you need to log the function so you could bring down the x and take derivative of it
baldymcgee6
  • baldymcgee6
would you agree that \[d/dx(2^x) = 2^xln(2)\]
baldymcgee6
  • baldymcgee6
anonymous
  • anonymous
yea doing derivatives of y= 2^x is different from e^x since you dont need to do logs for e^x ln(y) = xln(2) 1/y dy/dx = ln(2) dy/dx = yln(2) y' = 2^x ln(2)
AccessDenied
  • AccessDenied
Yes, this is just a specific case for the exponential rule: \(\large \frac{d}{dx}(e^x) = e^x \ln e = e^x * 1 = e^x \)
baldymcgee6
  • baldymcgee6
Thank you @AccessDenied
AccessDenied
  • AccessDenied
You're welcome. :)

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