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I still don't get it.

I messed up the labeling above... it is 51 deg 33 min and 18 deg 33 min (I put "sec" in for both)

Well what dont u get? what exactly is bothering you about this diagram?

do I divide 200 by tan(18+33/60)-tan(51+33/60)?

I'm not sure... why would you divide it by the difference in those two tangents?

i don't know. can you please just give me the answer?

\( \large {200 \over \tan(18+{33 \over 60}) }-{200 \over\tan(51+{33 \over 60})} \)

so the answer is -706.44 ft

noooo did you solve this?

How can distance be negative?

Are you on radians or degrees?

You must be on radians switch the mode to degrees

Yesss :)