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hba
 2 years ago
Best ResponseYou've already chosen the best response.1The easiest way to do this is to use implicit differentiation on it as it stands. You differentiate using the normal rules but you treat y as an unknown function of x. This means f(y) differentates to f '(y)*(dy/dx) by the chain rule. xy + x + y^2 = 6 First implicit differentiation gives [1*y + x*1*(dy/dx)] + 1 + 2y*(dy/dx) = 0 .....[from xy].....................[from y^2] You can rearrange this to give dy/dx = (function of x and y) Second implicit differentiation gives dy/dx + [1*(dy/dx) + x*(d2y/dx2)] + [2*(dy/dx)*(dy/dx) + 2y*(d2y/dx2)] = 0 ...................[from x*(dy/dx)]......................[from 2y*(dy/dx)] Now you replace each dy/dx by its function of x and y found above. Then rearrange it to give d2y/dx2 = (function of x and y).

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0i don't understand how you split it up, i'm confused.... that honestly made no sense

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0yay now my head hurts even worse

hba
 2 years ago
Best ResponseYou've already chosen the best response.1How Much More Questions Do You Have ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Or Is This The Last Question ?

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0this is my first question...

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0i've got about 16 more for this section, then 5 on a second section on it and a worksheet

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0i'm a junior in highschool taking calculus.. this isn't making sense

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0obviously not if this isn't making sense. sorry it's just frustrating!

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0and it's not making a bit of sense

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Well, (x^2)y + x(y^2) = 6 d/dx[(x^2)y + x(y^2)] = d/dx (6)

hba
 2 years ago
Best ResponseYou've already chosen the best response.12xy + dy/dx(x^2) + y^2 + 2y(dy/dx)x =0

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0how'd you get 2xy + dy/dx(x^2 + y^2 + 2y(dydx)x=0?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1You dont know how to differentiate ?

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0I do, but it's confusing me

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0you use the multiplication rule right? udv + vdu?

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0x^2(1) + y(2x) = 2xy + x^2

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Yes I am Using Product Rule

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0then how did you get 2xy then dy/dx x^2?

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0or do you get dy/dx and all that stuff in parenthasis because you're finding the d/dx of y

hba
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ dy }{ dx }[(x^2)y + x(y^2)] =\frac{ dy }{ dx }6\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1\[2xy + dy/dx(x^2) + y^2 + 2y(dy/dx)x =0\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Now Take The Terms Including dy/dx On One Side

hba
 2 years ago
Best ResponseYou've already chosen the best response.1\[dy/dx(x^2)+2y(dy/dx)x = y^22xy\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1\[dy/dx(x^2+2xy)=y^22xy\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1So,\[\frac{ dy }{ dx }=\frac{ (y^2+2xy)}{x^2+2xy }\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1^ Now Thats Your Answer Got It :)

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0question, when using the product rule

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0how do you know which one to put dy/dx with

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0like when we had x^2y and got dy/dx(x^2) + 2xy

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0why'd we put dy/dx with x^2 and not 2xy?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Well Its Your Own Decision Whether to Put U first or V First If We talk about the formula

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0okay but then which one do i put the dy/dx with?

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0like the next problem is y2 = (x+1)/(x1)

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0so would i do 2y (dy/dx) = vdu  udv/v^2

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0so dy/dx2y = (x+1)(1)  (x1)(1) / (x1)^2

hba
 2 years ago
Best ResponseYou've already chosen the best response.1@Godsgirl Please Help Her Out I Gotta Leave Thanks :)

Godsgirl
 2 years ago
Best ResponseYou've already chosen the best response.0Hey so wht do u need help with

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0I'm here. I have a question on where to put the dy/dx when solving

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0right now i'm working on y^2 = x1/x+1

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0so i take dy/dx y^2 = (x+1)(1)  (x1)(1) / (x+1)^2 right?

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0and the left side will equal 2y when i take dy/dx of it

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0now where do i keep dy/dx, when solving?

Godsgirl
 2 years ago
Best ResponseYou've already chosen the best response.0here i already solved it

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0where do i put it? because i know i need to get it alone

Godsgirl
 2 years ago
Best ResponseYou've already chosen the best response.0I sent it to u on ur messages

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0that's not the question i'm asking about..

Godsgirl
 2 years ago
Best ResponseYou've already chosen the best response.0which one are u asking about then

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0i'm not trying to come off as rude, i'm sorry!

hba
 2 years ago
Best ResponseYou've already chosen the best response.1differentiate both sides with respect to x

Godsgirl
 2 years ago
Best ResponseYou've already chosen the best response.0oh okay i was lost there

Godsgirl
 2 years ago
Best ResponseYou've already chosen the best response.0i see where shes at now

hba
 2 years ago
Best ResponseYou've already chosen the best response.1\[2y dy/dx = [(x+1)(x1)] /(x+1)^2 \]

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0so you keep dy/dx with the y on the left

jamroz
 2 years ago
Best ResponseYou've already chosen the best response.0but why? cause i had gotten that far, i just didn't know which side to leave dy/dx with?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Now You Got Which Side You Had To Keep It :) Anyways I am Off To Sleep, Aww My Head Hurts Anyways Bye :)
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