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hbaBest ResponseYou've already chosen the best response.1
The easiest way to do this is to use implicit differentiation on it as it stands. You differentiate using the normal rules but you treat y as an unknown function of x. This means f(y) differentates to f '(y)*(dy/dx) by the chain rule. xy + x + y^2 = 6 First implicit differentiation gives [1*y + x*1*(dy/dx)] + 1 + 2y*(dy/dx) = 0 .....[from xy].....................[from y^2] You can rearrange this to give dy/dx = (function of x and y) Second implicit differentiation gives dy/dx + [1*(dy/dx) + x*(d2y/dx2)] + [2*(dy/dx)*(dy/dx) + 2y*(d2y/dx2)] = 0 ...................[from x*(dy/dx)]......................[from 2y*(dy/dx)] Now you replace each dy/dx by its function of x and y found above. Then rearrange it to give d2y/dx2 = (function of x and y).
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
i don't understand how you split it up, i'm confused.... that honestly made no sense
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
yay now my head hurts even worse
 one year ago

hbaBest ResponseYou've already chosen the best response.1
How Much More Questions Do You Have ?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Or Is This The Last Question ?
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
this is my first question...
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
i've got about 16 more for this section, then 5 on a second section on it and a worksheet
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
i'm a junior in highschool taking calculus.. this isn't making sense
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
obviously not if this isn't making sense. sorry it's just frustrating!
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
and it's not making a bit of sense
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Well, (x^2)y + x(y^2) = 6 d/dx[(x^2)y + x(y^2)] = d/dx (6)
 one year ago

hbaBest ResponseYou've already chosen the best response.1
2xy + dy/dx(x^2) + y^2 + 2y(dy/dx)x =0
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
how'd you get 2xy + dy/dx(x^2 + y^2 + 2y(dydx)x=0?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
You dont know how to differentiate ?
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
I do, but it's confusing me
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
you use the multiplication rule right? udv + vdu?
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
x^2(1) + y(2x) = 2xy + x^2
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Yes I am Using Product Rule
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
then how did you get 2xy then dy/dx x^2?
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
or do you get dy/dx and all that stuff in parenthasis because you're finding the d/dx of y
 one year ago

hbaBest ResponseYou've already chosen the best response.1
\[\frac{ dy }{ dx }[(x^2)y + x(y^2)] =\frac{ dy }{ dx }6\]
 one year ago

hbaBest ResponseYou've already chosen the best response.1
\[2xy + dy/dx(x^2) + y^2 + 2y(dy/dx)x =0\]
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Now Take The Terms Including dy/dx On One Side
 one year ago

hbaBest ResponseYou've already chosen the best response.1
\[dy/dx(x^2)+2y(dy/dx)x = y^22xy\]
 one year ago

hbaBest ResponseYou've already chosen the best response.1
\[dy/dx(x^2+2xy)=y^22xy\]
 one year ago

hbaBest ResponseYou've already chosen the best response.1
So,\[\frac{ dy }{ dx }=\frac{ (y^2+2xy)}{x^2+2xy }\]
 one year ago

hbaBest ResponseYou've already chosen the best response.1
^ Now Thats Your Answer Got It :)
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
question, when using the product rule
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
how do you know which one to put dy/dx with
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
like when we had x^2y and got dy/dx(x^2) + 2xy
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
why'd we put dy/dx with x^2 and not 2xy?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Well Its Your Own Decision Whether to Put U first or V First If We talk about the formula
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
okay but then which one do i put the dy/dx with?
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
like the next problem is y2 = (x+1)/(x1)
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
so would i do 2y (dy/dx) = vdu  udv/v^2
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
so dy/dx2y = (x+1)(1)  (x1)(1) / (x1)^2
 one year ago

hbaBest ResponseYou've already chosen the best response.1
@Godsgirl Please Help Her Out I Gotta Leave Thanks :)
 one year ago

GodsgirlBest ResponseYou've already chosen the best response.0
Hey so wht do u need help with
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
I'm here. I have a question on where to put the dy/dx when solving
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
right now i'm working on y^2 = x1/x+1
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
so i take dy/dx y^2 = (x+1)(1)  (x1)(1) / (x+1)^2 right?
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
and the left side will equal 2y when i take dy/dx of it
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
now where do i keep dy/dx, when solving?
 one year ago

GodsgirlBest ResponseYou've already chosen the best response.0
here i already solved it
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
where do i put it? because i know i need to get it alone
 one year ago

GodsgirlBest ResponseYou've already chosen the best response.0
I sent it to u on ur messages
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
that's not the question i'm asking about..
 one year ago

GodsgirlBest ResponseYou've already chosen the best response.0
which one are u asking about then
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
i'm not trying to come off as rude, i'm sorry!
 one year ago

hbaBest ResponseYou've already chosen the best response.1
differentiate both sides with respect to x
 one year ago

GodsgirlBest ResponseYou've already chosen the best response.0
oh okay i was lost there
 one year ago

GodsgirlBest ResponseYou've already chosen the best response.0
i see where shes at now
 one year ago

hbaBest ResponseYou've already chosen the best response.1
\[2y dy/dx = [(x+1)(x1)] /(x+1)^2 \]
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
so you keep dy/dx with the y on the left
 one year ago

jamrozBest ResponseYou've already chosen the best response.0
but why? cause i had gotten that far, i just didn't know which side to leave dy/dx with?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Now You Got Which Side You Had To Keep It :) Anyways I am Off To Sleep, Aww My Head Hurts Anyways Bye :)
 one year ago
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