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i would probably start by rewriting it (x^2+3x-5)(x-1)^(1/3)

Okay should i do the chain rule?

i did product rule

u got it?

I got |dw:1350267174267:dw|

dont think thats correct

was the original problem (cuberoot(x)) - 1)

only the x is under the cube root?

Only the x under the cube root that where I get stuck

oh i did it \[\sqrt[3]{x-1}\]
so you might be right

I just couldnt decide whether or not to do the chain rule and what to do with the (-1) if I do

well this is a product rule
(x^2+3x-5) d/dx(cube root(x)-1) + (cube root(x)-1) d/dx(x^2+3x-5)

= (x^2+3x-5) 1/3 x^-2/3 + (x^1/3 - 1) (2x+3)

just algebra and reducing after this point

Okay thank you!