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Find y prime if y=(x^2+3x-5)(cube root(x)-1)

Mathematics
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i would probably start by rewriting it (x^2+3x-5)(x-1)^(1/3)
Okay should i do the chain rule?
i did product rule

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Other answers:

u got it?
I got |dw:1350267174267:dw|
dont think thats correct
was the original problem (cuberoot(x)) - 1)
only the x is under the cube root?
Only the x under the cube root that where I get stuck
oh i did it \[\sqrt[3]{x-1}\] so you might be right
I just couldnt decide whether or not to do the chain rule and what to do with the (-1) if I do
well this is a product rule (x^2+3x-5) d/dx(cube root(x)-1) + (cube root(x)-1) d/dx(x^2+3x-5)
= (x^2+3x-5) 1/3 x^-2/3 + (x^1/3 - 1) (2x+3)
just algebra and reducing after this point
Okay thank you!

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