## anonymous 3 years ago Find y prime if y=(x^2+3x-5)(cube root(x)-1)

1. anonymous

i would probably start by rewriting it (x^2+3x-5)(x-1)^(1/3)

2. anonymous

Okay should i do the chain rule?

3. anonymous

i did product rule

4. anonymous

u got it?

5. anonymous

I got |dw:1350267174267:dw|

6. anonymous

dont think thats correct

7. anonymous

was the original problem (cuberoot(x)) - 1)

8. anonymous

only the x is under the cube root?

9. anonymous

Only the x under the cube root that where I get stuck

10. anonymous

oh i did it $\sqrt[3]{x-1}$ so you might be right

11. anonymous

I just couldnt decide whether or not to do the chain rule and what to do with the (-1) if I do

12. anonymous

well this is a product rule (x^2+3x-5) d/dx(cube root(x)-1) + (cube root(x)-1) d/dx(x^2+3x-5)

13. anonymous

= (x^2+3x-5) 1/3 x^-2/3 + (x^1/3 - 1) (2x+3)

14. anonymous

just algebra and reducing after this point

15. anonymous

Okay thank you!