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ERoseM Group Title

Find y prime if y=(x^2+3x-5)(cube root(x)-1)

  • 2 years ago
  • 2 years ago

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  1. nickhouraney Group Title
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    i would probably start by rewriting it (x^2+3x-5)(x-1)^(1/3)

    • 2 years ago
  2. ERoseM Group Title
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    Okay should i do the chain rule?

    • 2 years ago
  3. nickhouraney Group Title
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    i did product rule

    • 2 years ago
  4. nickhouraney Group Title
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    u got it?

    • 2 years ago
  5. ERoseM Group Title
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    I got |dw:1350267174267:dw|

    • 2 years ago
  6. nickhouraney Group Title
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    dont think thats correct

    • 2 years ago
  7. nickhouraney Group Title
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    was the original problem (cuberoot(x)) - 1)

    • 2 years ago
  8. nickhouraney Group Title
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    only the x is under the cube root?

    • 2 years ago
  9. ERoseM Group Title
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    Only the x under the cube root that where I get stuck

    • 2 years ago
  10. nickhouraney Group Title
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    oh i did it \[\sqrt[3]{x-1}\] so you might be right

    • 2 years ago
  11. ERoseM Group Title
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    I just couldnt decide whether or not to do the chain rule and what to do with the (-1) if I do

    • 2 years ago
  12. nickhouraney Group Title
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    well this is a product rule (x^2+3x-5) d/dx(cube root(x)-1) + (cube root(x)-1) d/dx(x^2+3x-5)

    • 2 years ago
  13. nickhouraney Group Title
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    = (x^2+3x-5) 1/3 x^-2/3 + (x^1/3 - 1) (2x+3)

    • 2 years ago
  14. nickhouraney Group Title
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    just algebra and reducing after this point

    • 2 years ago
  15. ERoseM Group Title
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    Okay thank you!

    • 2 years ago
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