Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

find the derivative of f(x)=sqrt (x^2+2x)

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

\( f(x)=(x^2+2)^{1 \over 2}\)
thats not one of the choices

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

noooooooo its easier to solve in this format
\[1\div2\sqrt{x ^{2}+2x}\times(2x+2)\]
\( f(x)=(x^2+2)^{1 \over 2}\) is the same as \( f(x)= \sqrt{x^2+2}\)
Sandy, it's easier to differentiate a root if you rewrite it as a fractional exponent :) She was just rewriting the problem a little nicer for you, not the solution. :D
i understand but the assignment is keeping it that way so im getting confused thats all
it might be a good idea to switch to a fractional exponent, do the differentiation, then as your last step, put whatever fractional exponent you have back into root form. UNLESS you remember the derivative of sqrt(x), then you skip doing that step ^^
swiss is typing up a storm :P she prolly got something for you lol
she might just be trolling us, it's hard to tell at this point -_- lol
\(f(x)=(x^2+2)^{1 \over 2}\) \( {1 \over 2}(x^2+2)^{({1 \over 2}-1)}*2x\) \( {1 \over 2}(x^2+2)^{-1 \over 2}*2x\) \(\large { 1 \over 2\sqrt{x^2+2}}*2x\) \(\large {2x \over 2(x^2+2)}\) \(\large {x \over (x^2+2)}\)
okkk i had to post loil but if you are still interested I can explain what i did
Woops! Your sqrt disappeared on the last couple steps there! <:o
@zepdrix was getting too curious
i hate latex it never listens
ok one more time at it
ok thanks
you guys rock
Do the first 3 steps make sense though sandy? c: those she did correctly.
ok lets explain the first 3 steps that last 2 steps are basic simplification neways
u used the power rule first
I used the chain rule by first bringing down the exponent in front of the bracket and then subtracting one from the exponent as you can see and then I derived what was in the bracket. The derivative of x^2+2 is 2x
Well as we see there are 2 things that need to be derived. The outer exponent and the inner exponent. So the chain rule states that you first derive the outer part and then you derive what is in the bracket
Do you follow @sandy524
alrighty ill just give you the last two lines that i messed up \( \large {2x \over 2\sqrt{x^2+2}}\) \( \large {x \over \sqrt{x^2+2}}\)
i dont get what this means

Not the answer you are looking for?

Search for more explanations.

Ask your own question