A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
A mass m = 11.0 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5008.0 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.46. The mass leaves the spring at a speed v = 2.8 m/s.
3) The mass is measured to leave the rough spot with a final speed vf = 1.5 m/s.
How much work is done by friction as the mass crosses the rough spot?
What is the length of the rough spot?
In a new scenario, the block only makes it (exactly) halfway through the rough spot. How far was the spring compressed fro
anonymous
 4 years ago
A mass m = 11.0 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5008.0 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.46. The mass leaves the spring at a speed v = 2.8 m/s. 3) The mass is measured to leave the rough spot with a final speed vf = 1.5 m/s. How much work is done by friction as the mass crosses the rough spot? What is the length of the rough spot? In a new scenario, the block only makes it (exactly) halfway through the rough spot. How far was the spring compressed fro

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry, saw you were off line so thought you were gone for the evening...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let me look it over..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sure, so... work done by the rough spot (friction) = 1/2*11*( 1.5^2 2.8^2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0length of the rough spot is from Work = F*d = mu*mg*d

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now the last part should be clearer... it's a little tricky but not too tough...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find W= mu*mg*d/2 that's the KE the mass had when it encountered the patch (and also the KE when it left the spring) KE=PEspring mu*mg*d/2 = 1/2 *k*x^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you soo much ur a life savor litterally..i have 2 more questions i cant get .if you wouldnt mind helping me on those id appreciate it soo much

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0work energy theorem problems? you should be able to do them now... I'll answer any specific questions you have about particular details...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now i have conservative forces and potential energy problem
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.