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cbrezovs
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A mass m = 11.0 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5008.0 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.46. The mass leaves the spring at a speed v = 2.8 m/s.
3) The mass is measured to leave the rough spot with a final speed vf = 1.5 m/s.
How much work is done by friction as the mass crosses the rough spot?
What is the length of the rough spot?
In a new scenario, the block only makes it (exactly) halfway through the rough spot. How far was the spring compressed fro
 one year ago
 one year ago
cbrezovs Group Title
A mass m = 11.0 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5008.0 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.46. The mass leaves the spring at a speed v = 2.8 m/s. 3) The mass is measured to leave the rough spot with a final speed vf = 1.5 m/s. How much work is done by friction as the mass crosses the rough spot? What is the length of the rough spot? In a new scenario, the block only makes it (exactly) halfway through the rough spot. How far was the spring compressed fro
 one year ago
 one year ago

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Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
sorry, saw you were off line so thought you were gone for the evening...
 one year ago

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let me look it over..
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
sure, so... work done by the rough spot (friction) = 1/2*11*( 1.5^2 2.8^2)
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
length of the rough spot is from Work = F*d = mu*mg*d
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
now the last part should be clearer... it's a little tricky but not too tough...
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
find W= mu*mg*d/2 that's the KE the mass had when it encountered the patch (and also the KE when it left the spring) KE=PEspring mu*mg*d/2 = 1/2 *k*x^2
 one year ago

cbrezovs Group TitleBest ResponseYou've already chosen the best response.0
thank you soo much ur a life savor litterally..i have 2 more questions i cant get .if you wouldnt mind helping me on those id appreciate it soo much
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
work energy theorem problems? you should be able to do them now... I'll answer any specific questions you have about particular details...
 one year ago

cbrezovs Group TitleBest ResponseYou've already chosen the best response.0
now i have conservative forces and potential energy problem
 one year ago
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