anonymous
  • anonymous
A mass m = 11.0 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5008.0 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.46. The mass leaves the spring at a speed v = 2.8 m/s. 3) The mass is measured to leave the rough spot with a final speed vf = 1.5 m/s. How much work is done by friction as the mass crosses the rough spot? What is the length of the rough spot? In a new scenario, the block only makes it (exactly) half-way through the rough spot. How far was the spring compressed fro
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
sorry, saw you were off line so thought you were gone for the evening...
anonymous
  • anonymous
let me look it over..
anonymous
  • anonymous
sure, so... work done by the rough spot (friction) = 1/2*11*( 1.5^2 -2.8^2)

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anonymous
  • anonymous
length of the rough spot is from Work = F*d = mu*mg*d
anonymous
  • anonymous
now the last part should be clearer... it's a little tricky but not too tough...
anonymous
  • anonymous
find W= mu*mg*d/2 that's the KE the mass had when it encountered the patch (and also the KE when it left the spring) KE=PEspring mu*mg*d/2 = 1/2 *k*x^2
anonymous
  • anonymous
thank you soo much ur a life savor litterally..i have 2 more questions i cant get .if you wouldnt mind helping me on those id appreciate it soo much
anonymous
  • anonymous
work energy theorem problems? you should be able to do them now... I'll answer any specific questions you have about particular details...
anonymous
  • anonymous
now i have conservative forces and potential energy problem

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