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cbrezovs

  • 2 years ago

A mass m = 11.0 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5008.0 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.46. The mass leaves the spring at a speed v = 2.8 m/s. 3) The mass is measured to leave the rough spot with a final speed vf = 1.5 m/s. How much work is done by friction as the mass crosses the rough spot? What is the length of the rough spot? In a new scenario, the block only makes it (exactly) half-way through the rough spot. How far was the spring compressed fro

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  1. Algebraic!
    • 2 years ago
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    sorry, saw you were off line so thought you were gone for the evening...

  2. Algebraic!
    • 2 years ago
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    let me look it over..

  3. Algebraic!
    • 2 years ago
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    sure, so... work done by the rough spot (friction) = 1/2*11*( 1.5^2 -2.8^2)

  4. Algebraic!
    • 2 years ago
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    length of the rough spot is from Work = F*d = mu*mg*d

  5. Algebraic!
    • 2 years ago
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    now the last part should be clearer... it's a little tricky but not too tough...

  6. Algebraic!
    • 2 years ago
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    find W= mu*mg*d/2 that's the KE the mass had when it encountered the patch (and also the KE when it left the spring) KE=PEspring mu*mg*d/2 = 1/2 *k*x^2

  7. cbrezovs
    • 2 years ago
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    thank you soo much ur a life savor litterally..i have 2 more questions i cant get .if you wouldnt mind helping me on those id appreciate it soo much

  8. Algebraic!
    • 2 years ago
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    work energy theorem problems? you should be able to do them now... I'll answer any specific questions you have about particular details...

  9. cbrezovs
    • 2 years ago
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    now i have conservative forces and potential energy problem

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