A mass m = 11.0 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5008.0 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.46. The mass leaves the spring at a speed v = 2.8 m/s.
3) The mass is measured to leave the rough spot with a final speed vf = 1.5 m/s.
How much work is done by friction as the mass crosses the rough spot?
What is the length of the rough spot?
In a new scenario, the block only makes it (exactly) half-way through the rough spot. How far was the spring compressed fro
Stacey Warren - Expert brainly.com
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sorry, saw you were off line so thought you were gone for the evening...
let me look it over..
work done by the rough spot (friction) = 1/2*11*( 1.5^2 -2.8^2)