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sauravshakya
Group Title
What is the n th term of the series:
1+1+2+3+5+8+13+21+...
 2 years ago
 2 years ago
sauravshakya Group Title
What is the n th term of the series: 1+1+2+3+5+8+13+21+...
 2 years ago
 2 years ago

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Coolsector Group TitleBest ResponseYou've already chosen the best response.0
A(n) = A(n1) + A(n2) where a1 = 1 and a2 = 1 ?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
In terms of n
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Looks familiar....
 2 years ago

Samkeyv Group TitleBest ResponseYou've already chosen the best response.0
N th term is given by the formulae A(n)=A(n+1)+A(n+2) N=(n+1)+(n+2)
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
I know dw:1350296451209:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
But what in terms of n only.
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
it's funny that there is a question about the golden ratio now
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.4
it is fibonacci...
 2 years ago

kenttknguyen Group TitleBest ResponseYou've already chosen the best response.0
In terms of n > FIBOnnACCI
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.4
\[F_nF_{n1}F_{n2}=0 \ \ \ n\ge2\] setting up characterestic equation gives\[\lambda^2\lambda1=0\]wchich gives\[\phi_1=\frac{1+\sqrt{5}}{2}\]\[\phi_2=\frac{1\sqrt{5}}{2}\]and so\[F_n=A\phi_1^n+B\phi_2^n\]and all u need is finding A and B using the values of \(F_0\) and \(F_1\)
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
@mukushla how dw:1350297426979:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
oh I get it now...... thanx
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya may you explain how ?
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
i thought i got it but i realized that i was wrong
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
ok got it .. nvm :)
 2 years ago
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