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sauravshakya
Group Title
What is the n th term of the series:
1+1+2+3+5+8+13+21+...
 one year ago
 one year ago
sauravshakya Group Title
What is the n th term of the series: 1+1+2+3+5+8+13+21+...
 one year ago
 one year ago

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Coolsector Group TitleBest ResponseYou've already chosen the best response.0
A(n) = A(n1) + A(n2) where a1 = 1 and a2 = 1 ?
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
In terms of n
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Looks familiar....
 one year ago

Samkeyv Group TitleBest ResponseYou've already chosen the best response.0
N th term is given by the formulae A(n)=A(n+1)+A(n+2) N=(n+1)+(n+2)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
I know dw:1350296451209:dw
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
But what in terms of n only.
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
it's funny that there is a question about the golden ratio now
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.4
it is fibonacci...
 one year ago

kenttknguyen Group TitleBest ResponseYou've already chosen the best response.0
In terms of n > FIBOnnACCI
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.4
\[F_nF_{n1}F_{n2}=0 \ \ \ n\ge2\] setting up characterestic equation gives\[\lambda^2\lambda1=0\]wchich gives\[\phi_1=\frac{1+\sqrt{5}}{2}\]\[\phi_2=\frac{1\sqrt{5}}{2}\]and so\[F_n=A\phi_1^n+B\phi_2^n\]and all u need is finding A and B using the values of \(F_0\) and \(F_1\)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
@mukushla how dw:1350297426979:dw
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
oh I get it now...... thanx
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya may you explain how ?
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
i thought i got it but i realized that i was wrong
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
ok got it .. nvm :)
 one year ago
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