Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

CoolsectorBest ResponseYou've already chosen the best response.0
A(n) = A(n1) + A(n2) where a1 = 1 and a2 = 1 ?
 one year ago

SamkeyvBest ResponseYou've already chosen the best response.0
N th term is given by the formulae A(n)=A(n+1)+A(n+2) N=(n+1)+(n+2)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
I know dw:1350296451209:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
But what in terms of n only.
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
it's funny that there is a question about the golden ratio now
 one year ago

kenttknguyenBest ResponseYou've already chosen the best response.0
In terms of n > FIBOnnACCI
 one year ago

mukushlaBest ResponseYou've already chosen the best response.4
\[F_nF_{n1}F_{n2}=0 \ \ \ n\ge2\] setting up characterestic equation gives\[\lambda^2\lambda1=0\]wchich gives\[\phi_1=\frac{1+\sqrt{5}}{2}\]\[\phi_2=\frac{1\sqrt{5}}{2}\]and so\[F_n=A\phi_1^n+B\phi_2^n\]and all u need is finding A and B using the values of \(F_0\) and \(F_1\)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
@mukushla how dw:1350297426979:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
oh I get it now...... thanx
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
@sauravshakya may you explain how ?
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
i thought i got it but i realized that i was wrong
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
ok got it .. nvm :)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.