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rhondaycole

  • 2 years ago

Solve for x: x + = 15 x = −3 x = −1.5 x = 0 x = 3

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  1. surdawi
    • 2 years ago
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    x + what?

  2. lharrell97
    • 2 years ago
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    x + what??

  3. rhondaycole
    • 2 years ago
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    5 over 2x plus fifteen over 2

  4. hba
    • 2 years ago
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    \[x+\frac{ 5 }{ 2x }=15\]

  5. lharrell97
    • 2 years ago
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    5/2x+15/2 = 15x = −3x = −1.5x = 0x = 3 like that?

  6. rhondaycole
    • 2 years ago
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    yea

  7. hba
    • 2 years ago
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    Well You Dont Need To Really Need To Actually Solve It.Since You Have Answer Options You Can Put The Value And Check And When LHS And RHS Match Thats Your Answer

  8. lharrell97
    • 2 years ago
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    there is no answer....

  9. lharrell97
    • 2 years ago
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    at least none that i can find. but im pretty sure that @hba's answer is wrong... if you solve: x+5/2x=15 x+5=30x x=30x-5 x=0.16666666666666666666666666666667 unless that's an answer choice, idk...

  10. hba
    • 2 years ago
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    \[x+5/2x+15/2=15\]

  11. hba
    • 2 years ago
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    Btw We Dont Know What The Correct Question Is ?

  12. surdawi
    • 2 years ago
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    @rhondaycole can you rewrite the question using the equation button

  13. jazy
    • 2 years ago
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    @rhondaycole \[x + \frac{ 5 }{ 2x } = 15\]Multiply by 5.\[x + \frac{ 5 }{ 2x }(5) = 15(5)\]\[x + 2x = 75\]x + 2x = 3x SO: 3x = 75 Divide both sides by 3. x = 25

  14. jazy
    • 2 years ago
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    @surdawi @lharrell97 this right?

  15. surdawi
    • 2 years ago
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    @jazy not sure about the equation but you did a mistake at the beginning x + 5/2x = 15 when multiply by 5 it will be 5x + 25/2x = 75

  16. CliffSedge
    • 2 years ago
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    @jazy that doesn't work.

  17. vivalakoda
    • 2 years ago
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    You would multiply the denominator to get rid of the fraction, not the numerator.

  18. CliffSedge
    • 2 years ago
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    You would want to multiply by 2x to get it out of the denominator.

  19. jazy
    • 2 years ago
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    Oh yeah! I just realized that sorry! :/

  20. surdawi
    • 2 years ago
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    \[x + \frac{ 5 }{ 2x } =15\] \[(2x)*x + (2x)*\frac{ 5 }{ 2x } =(2x)*15\] \[2x^{2} + 5 = 30x\] \[2x^{2} -30 x +5 = 0\] can you try now @jazy

  21. surdawi
    • 2 years ago
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    but still we are not sure what is we got the question right

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