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rhondaycole Group Title

Solve for x: x + = 15 x = −3 x = −1.5 x = 0 x = 3

  • 2 years ago
  • 2 years ago

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  1. surdawi Group Title
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    x + what?

    • 2 years ago
  2. lharrell97 Group Title
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    x + what??

    • 2 years ago
  3. rhondaycole Group Title
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    5 over 2x plus fifteen over 2

    • 2 years ago
  4. hba Group Title
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    \[x+\frac{ 5 }{ 2x }=15\]

    • 2 years ago
  5. lharrell97 Group Title
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    5/2x+15/2 = 15x = −3x = −1.5x = 0x = 3 like that?

    • 2 years ago
  6. rhondaycole Group Title
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    yea

    • 2 years ago
  7. hba Group Title
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    Well You Dont Need To Really Need To Actually Solve It.Since You Have Answer Options You Can Put The Value And Check And When LHS And RHS Match Thats Your Answer

    • 2 years ago
  8. lharrell97 Group Title
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    there is no answer....

    • 2 years ago
  9. lharrell97 Group Title
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    at least none that i can find. but im pretty sure that @hba's answer is wrong... if you solve: x+5/2x=15 x+5=30x x=30x-5 x=0.16666666666666666666666666666667 unless that's an answer choice, idk...

    • 2 years ago
  10. hba Group Title
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    \[x+5/2x+15/2=15\]

    • 2 years ago
  11. hba Group Title
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    Btw We Dont Know What The Correct Question Is ?

    • 2 years ago
  12. surdawi Group Title
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    @rhondaycole can you rewrite the question using the equation button

    • 2 years ago
  13. jazy Group Title
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    @rhondaycole \[x + \frac{ 5 }{ 2x } = 15\]Multiply by 5.\[x + \frac{ 5 }{ 2x }(5) = 15(5)\]\[x + 2x = 75\]x + 2x = 3x SO: 3x = 75 Divide both sides by 3. x = 25

    • 2 years ago
  14. jazy Group Title
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    @surdawi @lharrell97 this right?

    • 2 years ago
  15. surdawi Group Title
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    @jazy not sure about the equation but you did a mistake at the beginning x + 5/2x = 15 when multiply by 5 it will be 5x + 25/2x = 75

    • 2 years ago
  16. CliffSedge Group Title
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    @jazy that doesn't work.

    • 2 years ago
  17. vivalakoda Group Title
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    You would multiply the denominator to get rid of the fraction, not the numerator.

    • 2 years ago
  18. CliffSedge Group Title
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    You would want to multiply by 2x to get it out of the denominator.

    • 2 years ago
  19. jazy Group Title
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    Oh yeah! I just realized that sorry! :/

    • 2 years ago
  20. surdawi Group Title
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    \[x + \frac{ 5 }{ 2x } =15\] \[(2x)*x + (2x)*\frac{ 5 }{ 2x } =(2x)*15\] \[2x^{2} + 5 = 30x\] \[2x^{2} -30 x +5 = 0\] can you try now @jazy

    • 2 years ago
  21. surdawi Group Title
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    but still we are not sure what is we got the question right

    • 2 years ago
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