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rhondaycole

Solve for x: x + = 15 x = −3 x = −1.5 x = 0 x = 3

  • one year ago
  • one year ago

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  1. surdawi
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    x + what?

    • one year ago
  2. lharrell97
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    x + what??

    • one year ago
  3. rhondaycole
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    5 over 2x plus fifteen over 2

    • one year ago
  4. hba
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    \[x+\frac{ 5 }{ 2x }=15\]

    • one year ago
  5. lharrell97
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    5/2x+15/2 = 15x = −3x = −1.5x = 0x = 3 like that?

    • one year ago
  6. rhondaycole
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    yea

    • one year ago
  7. hba
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    Well You Dont Need To Really Need To Actually Solve It.Since You Have Answer Options You Can Put The Value And Check And When LHS And RHS Match Thats Your Answer

    • one year ago
  8. lharrell97
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    there is no answer....

    • one year ago
  9. lharrell97
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    at least none that i can find. but im pretty sure that @hba's answer is wrong... if you solve: x+5/2x=15 x+5=30x x=30x-5 x=0.16666666666666666666666666666667 unless that's an answer choice, idk...

    • one year ago
  10. hba
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    \[x+5/2x+15/2=15\]

    • one year ago
  11. hba
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    Btw We Dont Know What The Correct Question Is ?

    • one year ago
  12. surdawi
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    @rhondaycole can you rewrite the question using the equation button

    • one year ago
  13. jazy
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    @rhondaycole \[x + \frac{ 5 }{ 2x } = 15\]Multiply by 5.\[x + \frac{ 5 }{ 2x }(5) = 15(5)\]\[x + 2x = 75\]x + 2x = 3x SO: 3x = 75 Divide both sides by 3. x = 25

    • one year ago
  14. jazy
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    @surdawi @lharrell97 this right?

    • one year ago
  15. surdawi
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    @jazy not sure about the equation but you did a mistake at the beginning x + 5/2x = 15 when multiply by 5 it will be 5x + 25/2x = 75

    • one year ago
  16. CliffSedge
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    @jazy that doesn't work.

    • one year ago
  17. vivalakoda
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    You would multiply the denominator to get rid of the fraction, not the numerator.

    • one year ago
  18. CliffSedge
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    You would want to multiply by 2x to get it out of the denominator.

    • one year ago
  19. jazy
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    Oh yeah! I just realized that sorry! :/

    • one year ago
  20. surdawi
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    \[x + \frac{ 5 }{ 2x } =15\] \[(2x)*x + (2x)*\frac{ 5 }{ 2x } =(2x)*15\] \[2x^{2} + 5 = 30x\] \[2x^{2} -30 x +5 = 0\] can you try now @jazy

    • one year ago
  21. surdawi
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    but still we are not sure what is we got the question right

    • one year ago
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