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400m run. I'm faster than my partner by 4sec/ 1m. My partner finished the run in 50seconds. how do I create an equation and solve for this ?
 one year ago
 one year ago
400m run. I'm faster than my partner by 4sec/ 1m. My partner finished the run in 50seconds. how do I create an equation and solve for this ?
 one year ago
 one year ago

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RubieBest ResponseYou've already chosen the best response.0
can you show your method ?
 one year ago

vipul92Best ResponseYou've already chosen the best response.0
so yur 8.25 so tim=400/8.25
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.0
Okay Rubie why don't we start by calculating the speed of your partner. Now you will have to calculate it in sec/m unless that was a typo earlier. I will let you do the calculation and step in if necessary.
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.0
vipul if you are wondering why I said to give it in sec/m it is because that is the way they gave the realtionship between the runners. I may not reply for a few minutes here I need to do something quickly.
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.0
no track your units. the numbers you gave me up there would render m/s the relationship they gave us was in s/m . you need to get those units
 one year ago

RubieBest ResponseYou've already chosen the best response.0
nvm.... i'll just leave this question out then o.0
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.0
50/400 is the correct first step giving you a speed of 0.125 s/m
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.0
Unfortunately I think you have a typo here as if you are faster than your partner by 4 s/m then your speed is 0.1254 = 3.75 s/m which is impossible
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.0
\[\frac{ s }{ m }\] or \[\frac{ m }{ s }\] which is the unit your relationship is given in?
 one year ago
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