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berrypicking
I have a questions that doesn't appear to be an equation. Not sure how to solve. What is the solution of sq rt.(5x+1) The possible sol'n are x =0; x=16 and x=0; x=16; x=16 and x=1
If you want to get a solution type an equation firstly.
Shouldn't there be an equals sign somewhere in the initial equation of sqrt*x+) ?
sorry sqrt(5x+1)
there is no = sign just the sq rt sign with 5x+1 under it Can it not be solved unless there is an = sign. Maybe something is missing.
Maybe look higher up sometimes my math textbook says like for all of these equations solve when equal to five or something like that.
I don't get what u r saying
ahhh I think I know what they mean now I think the equation is in the form y=sqrt(5x+1) which means they want you to solve for when it crosses the x axis. See if that sounds like something you have/are doing in class.
my lesson is solving sq rt and other radical equations
Maybe it means which solution sets are possible....
Unfortunately I cannot help you as a) I do not fully understand what you are asking and b) I have to go I have class in 15 minutes
I would like to see wording of exact question...
exact wording is: What is the solution of sq. rt (5x+1)?
The whole question....
that is the whole question
What about the solutions part?
possbile answers are x=0; x=16 and x=0; x=16; x=16 and x=1
It might be a typo in the question. The answers you gave imply sqrt(5x+1)= 1 or maybe sqrt(5x+1)= 9 are possible equations.
What is the solution of sq. rt (5x+1)? Possbile answers are x=0; x=16 and x=0; x=16; x=16 and x=1 That's what it says?
yea because if you solve for zeros you get 5x+1=0 5x=-1 x=-1/5
I tried solving for 0
I was thinking it's a typo but wasn't sure. Thought maybe I was missing something
As far as I can tell you seem to be missing a crucial piece of this question somewhere.
I would bet your are a victim here. If you post a scan of the page, it might make it obvious to us...