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berrypicking
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I have a questions that doesn't appear to be an equation. Not sure how to solve. What is the solution of sq rt.(5x+1) The possible sol'n are x =0; x=16 and x=0; x=16; x=16 and x=1
 one year ago
 one year ago
berrypicking Group Title
I have a questions that doesn't appear to be an equation. Not sure how to solve. What is the solution of sq rt.(5x+1) The possible sol'n are x =0; x=16 and x=0; x=16; x=16 and x=1
 one year ago
 one year ago

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klimenkov Group TitleBest ResponseYou've already chosen the best response.1
If you want to get a solution type an equation firstly.
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.0
Shouldn't there be an equals sign somewhere in the initial equation of sqrt*x+) ?
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.0
sorry sqrt(5x+1)
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
there is no = sign just the sq rt sign with 5x+1 under it Can it not be solved unless there is an = sign. Maybe something is missing.
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.0
Maybe look higher up sometimes my math textbook says like for all of these equations solve when equal to five or something like that.
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
I don't get what u r saying
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.0
ahhh I think I know what they mean now I think the equation is in the form y=sqrt(5x+1) which means they want you to solve for when it crosses the x axis. See if that sounds like something you have/are doing in class.
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
my lesson is solving sq rt and other radical equations
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Maybe it means which solution sets are possible....
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Some constraint....
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.0
Unfortunately I cannot help you as a) I do not fully understand what you are asking and b) I have to go I have class in 15 minutes
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
I would like to see wording of exact question...
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
exact wording is: What is the solution of sq. rt (5x+1)?
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
The whole question....
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
that is the whole question
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
What about the solutions part?
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
possbile answers are x=0; x=16 and x=0; x=16; x=16 and x=1
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
It might be a typo in the question. The answers you gave imply sqrt(5x+1)= 1 or maybe sqrt(5x+1)= 9 are possible equations.
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
What is the solution of sq. rt (5x+1)? Possbile answers are x=0; x=16 and x=0; x=16; x=16 and x=1 That's what it says?
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.0
yea because if you solve for zeros you get 5x+1=0 5x=1 x=1/5
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
exactly
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
I tried solving for 0
 one year ago

berrypicking Group TitleBest ResponseYou've already chosen the best response.0
I was thinking it's a typo but wasn't sure. Thought maybe I was missing something
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.0
As far as I can tell you seem to be missing a crucial piece of this question somewhere.
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
I would bet your are a victim here. If you post a scan of the page, it might make it obvious to us...
 one year ago
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