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berrypicking Group Title

I have a questions that doesn't appear to be an equation. Not sure how to solve. What is the solution of sq rt.(5x+1) The possible sol'n are x =0; x=16 and x=0; x=16; x=16 and x=1

  • one year ago
  • one year ago

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  1. klimenkov Group Title
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    If you want to get a solution type an equation firstly.

    • one year ago
  2. whatisthequestion Group Title
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    Shouldn't there be an equals sign somewhere in the initial equation of sqrt*x+) ?

    • one year ago
  3. whatisthequestion Group Title
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    sorry sqrt(5x+1)

    • one year ago
  4. berrypicking Group Title
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    there is no = sign just the sq rt sign with 5x+1 under it Can it not be solved unless there is an = sign. Maybe something is missing.

    • one year ago
  5. whatisthequestion Group Title
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    Maybe look higher up sometimes my math textbook says like for all of these equations solve when equal to five or something like that.

    • one year ago
  6. berrypicking Group Title
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    I don't get what u r saying

    • one year ago
  7. whatisthequestion Group Title
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    ahhh I think I know what they mean now I think the equation is in the form y=sqrt(5x+1) which means they want you to solve for when it crosses the x axis. See if that sounds like something you have/are doing in class.

    • one year ago
  8. berrypicking Group Title
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    my lesson is solving sq rt and other radical equations

    • one year ago
  9. estudier Group Title
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    Maybe it means which solution sets are possible....

    • one year ago
  10. estudier Group Title
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    Some constraint....

    • one year ago
  11. whatisthequestion Group Title
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    Unfortunately I cannot help you as a) I do not fully understand what you are asking and b) I have to go I have class in 15 minutes

    • one year ago
  12. estudier Group Title
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    I would like to see wording of exact question...

    • one year ago
  13. berrypicking Group Title
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    exact wording is: What is the solution of sq. rt (5x+1)?

    • one year ago
  14. estudier Group Title
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    The whole question....

    • one year ago
  15. berrypicking Group Title
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    that is the whole question

    • one year ago
  16. estudier Group Title
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    What about the solutions part?

    • one year ago
  17. berrypicking Group Title
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    possbile answers are x=0; x=16 and x=0; x=16; x=16 and x=1

    • one year ago
  18. phi Group Title
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    It might be a typo in the question. The answers you gave imply sqrt(5x+1)= 1 or maybe sqrt(5x+1)= 9 are possible equations.

    • one year ago
  19. estudier Group Title
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    What is the solution of sq. rt (5x+1)? Possbile answers are x=0; x=16 and x=0; x=16; x=16 and x=1 That's what it says?

    • one year ago
  20. whatisthequestion Group Title
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    yea because if you solve for zeros you get 5x+1=0 5x=-1 x=-1/5

    • one year ago
  21. berrypicking Group Title
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    exactly

    • one year ago
  22. berrypicking Group Title
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    I tried solving for 0

    • one year ago
  23. berrypicking Group Title
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    I was thinking it's a typo but wasn't sure. Thought maybe I was missing something

    • one year ago
  24. whatisthequestion Group Title
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    As far as I can tell you seem to be missing a crucial piece of this question somewhere.

    • one year ago
  25. phi Group Title
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    I would bet your are a victim here. If you post a scan of the page, it might make it obvious to us...

    • one year ago
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is replying to Can someone tell me what button the professor is hitting...

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