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berrypicking

  • 2 years ago

I have a questions that doesn't appear to be an equation. Not sure how to solve. What is the solution of sq rt.(5x+1) The possible sol'n are x =0; x=16 and x=0; x=16; x=16 and x=1

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  1. klimenkov
    • 2 years ago
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    If you want to get a solution type an equation firstly.

  2. whatisthequestion
    • 2 years ago
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    Shouldn't there be an equals sign somewhere in the initial equation of sqrt*x+) ?

  3. whatisthequestion
    • 2 years ago
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    sorry sqrt(5x+1)

  4. berrypicking
    • 2 years ago
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    there is no = sign just the sq rt sign with 5x+1 under it Can it not be solved unless there is an = sign. Maybe something is missing.

  5. whatisthequestion
    • 2 years ago
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    Maybe look higher up sometimes my math textbook says like for all of these equations solve when equal to five or something like that.

  6. berrypicking
    • 2 years ago
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    I don't get what u r saying

  7. whatisthequestion
    • 2 years ago
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    ahhh I think I know what they mean now I think the equation is in the form y=sqrt(5x+1) which means they want you to solve for when it crosses the x axis. See if that sounds like something you have/are doing in class.

  8. berrypicking
    • 2 years ago
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    my lesson is solving sq rt and other radical equations

  9. estudier
    • 2 years ago
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    Maybe it means which solution sets are possible....

  10. estudier
    • 2 years ago
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    Some constraint....

  11. whatisthequestion
    • 2 years ago
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    Unfortunately I cannot help you as a) I do not fully understand what you are asking and b) I have to go I have class in 15 minutes

  12. estudier
    • 2 years ago
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    I would like to see wording of exact question...

  13. berrypicking
    • 2 years ago
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    exact wording is: What is the solution of sq. rt (5x+1)?

  14. estudier
    • 2 years ago
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    The whole question....

  15. berrypicking
    • 2 years ago
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    that is the whole question

  16. estudier
    • 2 years ago
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    What about the solutions part?

  17. berrypicking
    • 2 years ago
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    possbile answers are x=0; x=16 and x=0; x=16; x=16 and x=1

  18. phi
    • 2 years ago
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    It might be a typo in the question. The answers you gave imply sqrt(5x+1)= 1 or maybe sqrt(5x+1)= 9 are possible equations.

  19. estudier
    • 2 years ago
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    What is the solution of sq. rt (5x+1)? Possbile answers are x=0; x=16 and x=0; x=16; x=16 and x=1 That's what it says?

  20. whatisthequestion
    • 2 years ago
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    yea because if you solve for zeros you get 5x+1=0 5x=-1 x=-1/5

  21. berrypicking
    • 2 years ago
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    exactly

  22. berrypicking
    • 2 years ago
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    I tried solving for 0

  23. berrypicking
    • 2 years ago
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    I was thinking it's a typo but wasn't sure. Thought maybe I was missing something

  24. whatisthequestion
    • 2 years ago
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    As far as I can tell you seem to be missing a crucial piece of this question somewhere.

  25. phi
    • 2 years ago
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    I would bet your are a victim here. If you post a scan of the page, it might make it obvious to us...

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