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\[\rm {8n + 3 - 6n \over 2} = {8n \over 2} + {3\over 2} - {6n \over 2}\]

does the /2 apply to the entire expression or just the 6n?

16n+6-6n/2

Or is it...\[\rm 8n + 3 - {6n \over 2}\]

@vipul92 Better to write \(\rm 8n + 3 - 3n\)

vipul collect like terms to get 10n+6/2 then factor out a two to get in simplest terms 5n+2

k i understand

the / goes with the whole expression

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