A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
f(x) = x^2 +2x 1
Solve f(f(x)) = f(x)
anonymous
 3 years ago
f(x) = x^2 +2x 1 Solve f(f(x)) = f(x)

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350309182854:dw

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.2we have f(f(x))  f(x) =0 or (x^2 + 2x1)^2 + (x^2 + 2x 1)  1 =0 its a quadratic in x^2 + 2x1 it'll give 2 real vales of that,, then we'll solve for x 4 roots shall be obtained..

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0is this correct ? f(f(x))=f(x) f(x)=f^1 (f(x)) f(x) = x to get x^2 +2x 1 = x so solving this : x^2+x1=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can't see the wood for the trees... The equation is f(x)^2 + 2f(x) 1 = f(x) > f(x)^2 + f(x) 1 = 0 as shubhamsrg said...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if we do it like this \[f(x)=(x+1)^{2}2 \implies f(f(x))=(f(x)+1)^{2}2\] using it in the given equation we have \[f(x)=(f(x)+1)^{2}2\] putting the value of f(x) \[(x+1)^{2}2=((x+1)^{2}2+1)^{2}2\] solving that we get \[x+1=(x+1)^{2}1\] and then solve again
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.