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homework eight part one i am okay with the rest but dont understand the first bit
 one year ago
 one year ago
homework eight part one i am okay with the rest but dont understand the first bit
 one year ago
 one year ago

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hejåBest ResponseYou've already chosen the best response.0
H8P1 IMPULSE The impulse response is a concept often used in electrical engineering, because it fully characterizes the reaction of a linear system as a function of time. As a first step, we will learn the techniques used to calculate the impulse response of a given system. Consider the circuit shown below. Assume that both the capacitor and the inductor have been left in their relaxed states for a very long time. The voltage source is driven by a signal of vin=δ(t), that is a unit impulse at time t=0. R1=10Ω, L=5mH, R2=10kΩ, C=33nF. (a) What is the value of vR1(t) at t=0−? incorrect (b)Derive a differential equation expression for vR1(t), the voltage across the resistor in series with our inductor. What is the value of vR(t) at t=0+? Hint: it may be helpful to know that ∫0+0−δ(t)dt=1 incorrect (c)Assuming an exponential decay, what is the value for vR(t) at t=1ms? incorrect (d)Similarly, derive a differential equation expression for vC(t), the voltage across our capacitor. What is the value of vC(t) at t=0+? incorrect (e)What is the value for vC(t) at t=1ms?
 one year ago

EliteTUMBest ResponseYou've already chosen the best response.4
Well, I can answer H8P1 (a), which is simply "0V". The time is t = 0s, so JUST before the Impulse will start. So the supplied voltage is zero and therefore all voltages in the network are 0. Still working on Question (b)(e).
 one year ago

EliteTUMBest ResponseYou've already chosen the best response.4
ok, I got all of them now. I do all calcs with MatLab since I like scripting :) so: R1 = 10; R2 = 10000; C = 33*10^9; L = 5 * 10^3; t0 = 0; t0plus = 1; t0min = 0; tms = 0.001; %Q1 v_R1_0min = R1/L * exp(t0*R1/L) * t0min % Q2 (see: http://en.wikipedia.org/wiki/RL_circuit#Impulse_response ) v_r1_0plus = R1/L * exp(t0*R1/L) * t0plus % Q3 (see: http://en.wikipedia.org/wiki/RL_circuit#Impulse_response ) v_r1_1ms = R1/L * exp(tms*R1/L) * t0plus % Q4 (see: http://en.wikipedia.org/wiki/RC_circuit#Impulse_response ) v_c_0plus = 1/(R2*C) * exp(t0/(R2*C)) * t0plus % Q5 (see: http://en.wikipedia.org/wiki/RC_circuit#Impulse_response ) v_c_0plus = 1/(R2*C) * exp(tms/(R2*C)) * t0plus Values then are: v_R1_0min = 0 v_r1_0plus = 2000 v_r1_1ms = 270.6706 v_c_0plus = 3.0303e+003 v_c_0plus = 146.3667
 one year ago

olimpiacajBest ResponseYou've already chosen the best response.1
v_c_0plus is rong dude
 one year ago

EliteTUMBest ResponseYou've already chosen the best response.4
That's scientific notation! v_c_0plus = 3.0303e+003 = 3030.3 Also check your values for R1, R2, C, L and the times. But for me it's correct. Only one point missing for H8P3.
 one year ago

1431mahiBest ResponseYou've already chosen the best response.0
remove "+" sign its enough
 one year ago
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