anonymous
  • anonymous
Give two different numbers, each of which is the square of the other!
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

klimenkov
  • klimenkov
Complex number or real?
anonymous
  • anonymous
interesting.
anonymous
  • anonymous
1

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
two different numbers.
anonymous
  • anonymous
Just realized that
klimenkov
  • klimenkov
Solve[{x == y^2, y == x^2}, {x, y}] {{x -> 0, y -> 0}, {x -> 1, y -> 1}, {x -> -(-1)^(1/3), y -> (-1)^(2/3)}, {x -> (-1)^(2/3), y -> -(-1)^(1/3)}}
klimenkov
  • klimenkov
Only in complex they will be different.
anonymous
  • anonymous
i will say \(\frac{1}{2}+\frac{\sqrt{3}}{2}i\) and its conjugate
klimenkov
  • klimenkov
@jazy = lazy
anonymous
  • anonymous
I'm not at this level of math yet. I posted because I thought it to be a good answer, not because I was too lazy to help and do it myself. However I'll take it off it bothers. (:

Looking for something else?

Not the answer you are looking for? Search for more explanations.