## anonymous 3 years ago Give two different numbers, each of which is the square of the other!

1. klimenkov

Complex number or real?

2. anonymous

interesting.

3. anonymous

1

4. anonymous

two different numbers.

5. anonymous

Just realized that

6. klimenkov

Solve[{x == y^2, y == x^2}, {x, y}] {{x -> 0, y -> 0}, {x -> 1, y -> 1}, {x -> -(-1)^(1/3), y -> (-1)^(2/3)}, {x -> (-1)^(2/3), y -> -(-1)^(1/3)}}

7. klimenkov

Only in complex they will be different.

8. anonymous

i will say $$\frac{1}{2}+\frac{\sqrt{3}}{2}i$$ and its conjugate

9. klimenkov

@jazy = lazy

10. anonymous

I'm not at this level of math yet. I posted because I thought it to be a good answer, not because I was too lazy to help and do it myself. However I'll take it off it bothers. (: