A community for students.
Here's the question you clicked on:
 0 viewing
theEric
 3 years ago
Math proof help, please! Relations and subsets involved. I don't see the solution!
My math book proved that if sets \[A, B,C,D\] existed such that \[A \subseteq C \]and\[B \subseteq D\] then \[(A \times B) \subseteq (C \times D)\]
I need to show that the converse of that is false. I think the converse is\[(A \times B) \subseteq (C \times D)\]implies\[A \subseteq C \]and\[B \subseteq D\].
But I can't understand how it is false for some group of sets \[A,B,C,D\].
theEric
 3 years ago
Math proof help, please! Relations and subsets involved. I don't see the solution! My math book proved that if sets \[A, B,C,D\] existed such that \[A \subseteq C \]and\[B \subseteq D\] then \[(A \times B) \subseteq (C \times D)\] I need to show that the converse of that is false. I think the converse is\[(A \times B) \subseteq (C \times D)\]implies\[A \subseteq C \]and\[B \subseteq D\]. But I can't understand how it is false for some group of sets \[A,B,C,D\].

This Question is Closed

theEric
 3 years ago
Best ResponseYou've already chosen the best response.0Alright, thanks.. I never went into writing a proof on that, but I thought about it and didn't see it working... Thank you!

theEric
 3 years ago
Best ResponseYou've already chosen the best response.0Ah!! I think I finally see it.. Thanks for making me concentrate more on the null set issue!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.