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|dw:1350320124515:dw|

any method just explain

|dw:1350320261447:dw|
my graph

If |x| = y, then x = y OR x = -y

yes i get that part,
so this gives
|dw:1350321371149:dw|

There must be one for which x/2 + 3 is negative. That's an impossibility.

Because x/2 + 3 is the absolute value of something...?

|dw:1350321988874:dw|
|dw:1350322071606:dw|

so what would my final answers be

Are you sure about the first part?

I think it should be -3 (+ or -) sqrt (21)

oh wait, sorry... my bad

in any case, -3-sqrt(17), try substituting that for x in
x/2 + 3

And remember
-3-sqrt(17) < -3-sqrt(16) = -7

thank you!

No problem... Sorry about my pathetic arithmetic :P

still made sense in a way :P