anonymous
  • anonymous
(x+1)(x+2)(x+3)(x+4) = 99 (by hand)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[t=x^2+5x\]
shubhamsrg
  • shubhamsrg
that was pure genius !
anonymous
  • anonymous
ty :)

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anonymous
  • anonymous
Enlighten me....
anonymous
  • anonymous
Or better, tell me what t is?
shubhamsrg
  • shubhamsrg
(x+1)(x+4)(x+2)(x+3) = 99 (x^2 + 5x +4)(x^2 + 5x + 6) = 99 => (x^2 + 5x)^2 + 10 (x^2 + 5x) + 75 = 0 easier after that..
anonymous
  • anonymous
(x^2 + 5x +4)(x^2 + 5x + 6) = 99 (y-1)(y+1) = 99
shubhamsrg
  • shubhamsrg
aha,,cool !
anonymous
  • anonymous
ya much simpler :)
anonymous
  • anonymous
Yours is also a timesaver:-)
anonymous
  • anonymous
It will work whenever there is a sequence (arithmetic) or some symmetry (like 1,5,7,11)

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