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estudier

  • 3 years ago

(x+1)(x+2)(x+3)(x+4) = 99 (by hand)

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  1. mukushla
    • 3 years ago
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    \[t=x^2+5x\]

  2. shubhamsrg
    • 3 years ago
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    that was pure genius !

  3. mukushla
    • 3 years ago
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    ty :)

  4. estudier
    • 3 years ago
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    Enlighten me....

  5. estudier
    • 3 years ago
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    Or better, tell me what t is?

  6. shubhamsrg
    • 3 years ago
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    (x+1)(x+4)(x+2)(x+3) = 99 (x^2 + 5x +4)(x^2 + 5x + 6) = 99 => (x^2 + 5x)^2 + 10 (x^2 + 5x) + 75 = 0 easier after that..

  7. estudier
    • 3 years ago
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    (x^2 + 5x +4)(x^2 + 5x + 6) = 99 (y-1)(y+1) = 99

  8. shubhamsrg
    • 3 years ago
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    aha,,cool !

  9. mukushla
    • 3 years ago
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    ya much simpler :)

  10. estudier
    • 3 years ago
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    Yours is also a timesaver:-)

  11. estudier
    • 3 years ago
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    It will work whenever there is a sequence (arithmetic) or some symmetry (like 1,5,7,11)

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