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picture ina sec
How do I solve this?
that can't be right i ended up with 119 :l
What do you know about incenters?
m∠A = 58 m∠B = 64 m∠C = 58 The triangle has it's 3 Medians marked(D,E,F). A median cut's exactly half way from a vertex to the opposite side... It bisects the line segment and angle. So angle BCE would be half of angle C's measurement.
yea because it wants angle c... And C is bisected so its halfed
i think angle at C is getting bisect.. which means its dividing the angle in half.. so just half the angle of C
which is 29
thanks guys :)
yea it was 29 I just sent my quiz
@jazy, the incenter is the intersection of the angle bisectors. The medians are not involved. "A median cut's exactly half way from a vertex to the opposite side... It bisects the line segment and angle." This statement is false.
yes incenter is the bisectors and circumcenter is the perpandicular bisectors. I do not know where the medians are involved
what is the median of a triangle?
A median bisects a side of the triangle, but it doesn't necessarily also bisect the angle. |dw:1350322892891:dw|
In triangle ABC (that I drew), AN is an angle bisector and passes through the incenter of the triangle. CM is a median and makes AM = MB. It is not also an angle bisector of ACB. ACM =/= MCB.
|dw:1350323109326:dw| correction to the drawing.
I see so it intersects at the middle of a line but doesnt always bisect
Medians bisect sides. The three medians intersect at the centroid. Angle bisectors bisect angles. The three angle bisectors intersect at the incenter.
alright i got yea
Play around over here for a while http://www.mathopenref.com/triangleincenter.html @jazy you too.
k, thanks for the explanation @CliffSedge (: