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kaiteDID

  • 3 years ago

Finish these three solutions to this equation. Y= x-1/2

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  1. kaiteDID
    • 3 years ago
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    ( ,1/2,) ( ,3/2) ( ,5/2) i forgot to give this sorry

  2. amorfide
    • 3 years ago
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    you are given the y values substitute y=1/2 make x the subject substitute y=3/2 do the same y=5/2 do the same

  3. kaiteDID
    • 3 years ago
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    how do i do it i dont know how to do it.

  4. kaiteDID
    • 3 years ago
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    @Sir_Rico_of_Eureka can u help nobody explain how to do this if someone would explain how to get one i can get the others can u plz help me

  5. Sir_Rico_of_Eureka
    • 3 years ago
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    If you think about each set of numbers as (x,y) It will be easier to visualize it. \[y=x-\frac{ 1 }{ 2}\] Set y equal to 1/2. 3/2. and 5/2. You'll get 1/2 = x- 1/2, 3/2=x-1/2 and 5/2=x-1/2

  6. Sir_Rico_of_Eureka
    • 3 years ago
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    Can you solve the rest?

  7. kaiteDID
    • 3 years ago
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    i get how to do all that it's just i dont know how to get the answer

  8. Sir_Rico_of_Eureka
    • 3 years ago
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    You want to get x on its own. Subtract \[\frac{ 1 }{ 2 } \] from boths sides. For all the equations. \[\frac{ 1 }{ 2 } = x-\frac{ 1 }{ 2 }\] \[\frac{ 3 }{ 2 } = x -\frac{ 1 }{ 2 }\] \[\frac{ 5 }{ 2 } = x - \frac{ 1 }{ 2 }\]

  9. kaiteDID
    • 3 years ago
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    so the 1/2n one would be zero right?

  10. Sir_Rico_of_Eureka
    • 3 years ago
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    Yes :)

  11. Sir_Rico_of_Eureka
    • 3 years ago
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    OHHHHH NOOOO!

  12. Sir_Rico_of_Eureka
    • 3 years ago
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    I meant ADD! I'm soooo sorry.

  13. kaiteDID
    • 3 years ago
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    what? lol

  14. kaiteDID
    • 3 years ago
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    o okay

  15. kaiteDID
    • 3 years ago
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    so 1/2 would = 2/2=1

  16. Sir_Rico_of_Eureka
    • 3 years ago
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    :]

  17. Sir_Rico_of_Eureka
    • 3 years ago
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    Yup

  18. kaiteDID
    • 3 years ago
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    3/2=6/2=3

  19. Sir_Rico_of_Eureka
    • 3 years ago
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    3/2 + 1/2 = 4/2 = 2

  20. kaiteDID
    • 3 years ago
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    sorry add wrong lol

  21. kaiteDID
    • 3 years ago
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    5/2=6/2=3

  22. kaiteDID
    • 3 years ago
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    thank you for ur help i see how to do it now

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