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kaiteDID

Finish these three solutions to this equation. Y= x-1/2

  • one year ago
  • one year ago

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  1. kaiteDID
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    ( ,1/2,) ( ,3/2) ( ,5/2) i forgot to give this sorry

    • one year ago
  2. amorfide
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    you are given the y values substitute y=1/2 make x the subject substitute y=3/2 do the same y=5/2 do the same

    • one year ago
  3. kaiteDID
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    how do i do it i dont know how to do it.

    • one year ago
  4. kaiteDID
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    @Sir_Rico_of_Eureka can u help nobody explain how to do this if someone would explain how to get one i can get the others can u plz help me

    • one year ago
  5. Sir_Rico_of_Eureka
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    If you think about each set of numbers as (x,y) It will be easier to visualize it. \[y=x-\frac{ 1 }{ 2}\] Set y equal to 1/2. 3/2. and 5/2. You'll get 1/2 = x- 1/2, 3/2=x-1/2 and 5/2=x-1/2

    • one year ago
  6. Sir_Rico_of_Eureka
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    Can you solve the rest?

    • one year ago
  7. kaiteDID
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    i get how to do all that it's just i dont know how to get the answer

    • one year ago
  8. Sir_Rico_of_Eureka
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    You want to get x on its own. Subtract \[\frac{ 1 }{ 2 } \] from boths sides. For all the equations. \[\frac{ 1 }{ 2 } = x-\frac{ 1 }{ 2 }\] \[\frac{ 3 }{ 2 } = x -\frac{ 1 }{ 2 }\] \[\frac{ 5 }{ 2 } = x - \frac{ 1 }{ 2 }\]

    • one year ago
  9. kaiteDID
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    so the 1/2n one would be zero right?

    • one year ago
  10. Sir_Rico_of_Eureka
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    Yes :)

    • one year ago
  11. Sir_Rico_of_Eureka
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    OHHHHH NOOOO!

    • one year ago
  12. Sir_Rico_of_Eureka
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    I meant ADD! I'm soooo sorry.

    • one year ago
  13. kaiteDID
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    what? lol

    • one year ago
  14. kaiteDID
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    o okay

    • one year ago
  15. kaiteDID
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    so 1/2 would = 2/2=1

    • one year ago
  16. Sir_Rico_of_Eureka
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    :]

    • one year ago
  17. Sir_Rico_of_Eureka
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    Yup

    • one year ago
  18. kaiteDID
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    3/2=6/2=3

    • one year ago
  19. Sir_Rico_of_Eureka
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    3/2 + 1/2 = 4/2 = 2

    • one year ago
  20. kaiteDID
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    sorry add wrong lol

    • one year ago
  21. kaiteDID
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    5/2=6/2=3

    • one year ago
  22. kaiteDID
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    thank you for ur help i see how to do it now

    • one year ago
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