kaiteDID
Finish these three solutions to this equation.
Y= x-1/2
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kaiteDID
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( ,1/2,) ( ,3/2) ( ,5/2) i forgot to give this sorry
amorfide
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you are given the y values
substitute y=1/2
make x the subject
substitute y=3/2
do the same
y=5/2
do the same
kaiteDID
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how do i do it i dont know how to do it.
kaiteDID
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@Sir_Rico_of_Eureka can u help nobody explain how to do this if someone would explain how to get one i can get the others can u plz help me
Sir_Rico_of_Eureka
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If you think about each set of numbers as (x,y) It will be easier to visualize it. \[y=x-\frac{ 1 }{ 2}\] Set y equal to 1/2. 3/2. and 5/2.
You'll get 1/2 = x- 1/2, 3/2=x-1/2 and 5/2=x-1/2
Sir_Rico_of_Eureka
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Can you solve the rest?
kaiteDID
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i get how to do all that it's just i dont know how to get the answer
Sir_Rico_of_Eureka
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You want to get x on its own.
Subtract \[\frac{ 1 }{ 2 } \] from boths sides. For all the equations.
\[\frac{ 1 }{ 2 } = x-\frac{ 1 }{ 2 }\]
\[\frac{ 3 }{ 2 } = x -\frac{ 1 }{ 2 }\]
\[\frac{ 5 }{ 2 } = x - \frac{ 1 }{ 2 }\]
kaiteDID
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so the 1/2n one would be zero right?
Sir_Rico_of_Eureka
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I meant ADD! I'm soooo sorry.
kaiteDID
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what? lol
kaiteDID
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o okay
kaiteDID
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so 1/2 would = 2/2=1
kaiteDID
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3/2=6/2=3
Sir_Rico_of_Eureka
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3/2 + 1/2 = 4/2 = 2
kaiteDID
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sorry add wrong lol
kaiteDID
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5/2=6/2=3
kaiteDID
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thank you for ur help i see how to do it now