kaiteDID Group Title Finish these three solutions to this equation. Y= x-1/2 one year ago one year ago

1. kaiteDID Group Title

( ,1/2,) ( ,3/2) ( ,5/2) i forgot to give this sorry

2. amorfide Group Title

you are given the y values substitute y=1/2 make x the subject substitute y=3/2 do the same y=5/2 do the same

3. kaiteDID Group Title

how do i do it i dont know how to do it.

4. kaiteDID Group Title

@Sir_Rico_of_Eureka can u help nobody explain how to do this if someone would explain how to get one i can get the others can u plz help me

5. Sir_Rico_of_Eureka Group Title

If you think about each set of numbers as (x,y) It will be easier to visualize it. $y=x-\frac{ 1 }{ 2}$ Set y equal to 1/2. 3/2. and 5/2. You'll get 1/2 = x- 1/2, 3/2=x-1/2 and 5/2=x-1/2

6. Sir_Rico_of_Eureka Group Title

Can you solve the rest?

7. kaiteDID Group Title

i get how to do all that it's just i dont know how to get the answer

8. Sir_Rico_of_Eureka Group Title

You want to get x on its own. Subtract $\frac{ 1 }{ 2 }$ from boths sides. For all the equations. $\frac{ 1 }{ 2 } = x-\frac{ 1 }{ 2 }$ $\frac{ 3 }{ 2 } = x -\frac{ 1 }{ 2 }$ $\frac{ 5 }{ 2 } = x - \frac{ 1 }{ 2 }$

9. kaiteDID Group Title

so the 1/2n one would be zero right?

10. Sir_Rico_of_Eureka Group Title

Yes :)

11. Sir_Rico_of_Eureka Group Title

OHHHHH NOOOO!

12. Sir_Rico_of_Eureka Group Title

I meant ADD! I'm soooo sorry.

13. kaiteDID Group Title

what? lol

14. kaiteDID Group Title

o okay

15. kaiteDID Group Title

so 1/2 would = 2/2=1

16. Sir_Rico_of_Eureka Group Title

:]

17. Sir_Rico_of_Eureka Group Title

Yup

18. kaiteDID Group Title

3/2=6/2=3

19. Sir_Rico_of_Eureka Group Title

3/2 + 1/2 = 4/2 = 2

20. kaiteDID Group Title