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kaiteDID
 2 years ago
Best ResponseYou've already chosen the best response.0( ,1/2,) ( ,3/2) ( ,5/2) i forgot to give this sorry

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0you are given the y values substitute y=1/2 make x the subject substitute y=3/2 do the same y=5/2 do the same

kaiteDID
 2 years ago
Best ResponseYou've already chosen the best response.0how do i do it i dont know how to do it.

kaiteDID
 2 years ago
Best ResponseYou've already chosen the best response.0@Sir_Rico_of_Eureka can u help nobody explain how to do this if someone would explain how to get one i can get the others can u plz help me

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.1If you think about each set of numbers as (x,y) It will be easier to visualize it. \[y=x\frac{ 1 }{ 2}\] Set y equal to 1/2. 3/2. and 5/2. You'll get 1/2 = x 1/2, 3/2=x1/2 and 5/2=x1/2

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.1Can you solve the rest?

kaiteDID
 2 years ago
Best ResponseYou've already chosen the best response.0i get how to do all that it's just i dont know how to get the answer

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.1You want to get x on its own. Subtract \[\frac{ 1 }{ 2 } \] from boths sides. For all the equations. \[\frac{ 1 }{ 2 } = x\frac{ 1 }{ 2 }\] \[\frac{ 3 }{ 2 } = x \frac{ 1 }{ 2 }\] \[\frac{ 5 }{ 2 } = x  \frac{ 1 }{ 2 }\]

kaiteDID
 2 years ago
Best ResponseYou've already chosen the best response.0so the 1/2n one would be zero right?

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.1OHHHHH NOOOO!

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.1I meant ADD! I'm soooo sorry.

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.13/2 + 1/2 = 4/2 = 2

kaiteDID
 2 years ago
Best ResponseYou've already chosen the best response.0thank you for ur help i see how to do it now
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