anonymous
  • anonymous
i need to complete the square of -36x^2-36x+27
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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sasogeek
  • sasogeek
have you tried solving this?
anonymous
  • anonymous
yes. initially i divided each variable by 36, but then i got a bunch of fractions and it did not make sense to me. Do i need to divide by 36?
sasogeek
  • sasogeek
ok well that's a good start :) and yes you will end up with a bunch of fractions, it happens ;) i'll tell you what to do, try that, then let me know what answer you get... are we good?

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anonymous
  • anonymous
yes! please
anonymous
  • anonymous
ok, i got x^2+x+(1/2)^2=-27/36-1/4
sasogeek
  • sasogeek
uhhh close, but not quite. you should've divided by -36 that way you'd have \(\large x^2+x=\frac{27}{36}\)
sasogeek
  • sasogeek
sorry for late reply, i lost connection
anonymous
  • anonymous
ok, im going to try that. no problem, im doing some other problems while i wait
sasogeek
  • sasogeek
then with the next step, you'd get \(\large x^2+x+\frac{1}{4}=\frac{27}{36}+\frac{1}{4} \)
anonymous
  • anonymous
ok, i have x^2+x+1/4=1/2
sasogeek
  • sasogeek
\(\large \frac{27}{36}+\frac{1}{4}= what? \)
anonymous
  • anonymous
oops, i subtracted instead of adding. so 1?
sasogeek
  • sasogeek
yeah :)
anonymous
  • anonymous
ok, now im a little confused, isnt it (x+b/2)^2. i dont know where to go from here
sasogeek
  • sasogeek
ok so you have \(\huge x^2+x+\frac{1}{4}=1 \) what you said is right, b=1, hence the next step is \(\huge (x+\frac{1}{2})^2=1\) :)
anonymous
  • anonymous
so the answer is 1-(x+(1/2))^2
sasogeek
  • sasogeek
no... i keep losing connection so bear with the reply timing :) what you do is solve for x.... the next step is to find the square root of both sides of the equation to clear the square on the left side... \(\huge x+\frac{1}{2}= \pm \sqrt{1}\) \(\huge x= \pm \sqrt{1}-\frac{1}{2} \) \(\huge x= \pm 1-\frac{1}{2} \) solve for x now :)

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