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bmorg980
 3 years ago
i need to complete the square of 36x^236x+27
bmorg980
 3 years ago
i need to complete the square of 36x^236x+27

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sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0have you tried solving this?

bmorg980
 3 years ago
Best ResponseYou've already chosen the best response.0yes. initially i divided each variable by 36, but then i got a bunch of fractions and it did not make sense to me. Do i need to divide by 36?

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0ok well that's a good start :) and yes you will end up with a bunch of fractions, it happens ;) i'll tell you what to do, try that, then let me know what answer you get... are we good?

bmorg980
 3 years ago
Best ResponseYou've already chosen the best response.0ok, i got x^2+x+(1/2)^2=27/361/4

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0uhhh close, but not quite. you should've divided by 36 that way you'd have \(\large x^2+x=\frac{27}{36}\)

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0sorry for late reply, i lost connection

bmorg980
 3 years ago
Best ResponseYou've already chosen the best response.0ok, im going to try that. no problem, im doing some other problems while i wait

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0then with the next step, you'd get \(\large x^2+x+\frac{1}{4}=\frac{27}{36}+\frac{1}{4} \)

bmorg980
 3 years ago
Best ResponseYou've already chosen the best response.0ok, i have x^2+x+1/4=1/2

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0\(\large \frac{27}{36}+\frac{1}{4}= what? \)

bmorg980
 3 years ago
Best ResponseYou've already chosen the best response.0oops, i subtracted instead of adding. so 1?

bmorg980
 3 years ago
Best ResponseYou've already chosen the best response.0ok, now im a little confused, isnt it (x+b/2)^2. i dont know where to go from here

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0ok so you have \(\huge x^2+x+\frac{1}{4}=1 \) what you said is right, b=1, hence the next step is \(\huge (x+\frac{1}{2})^2=1\) :)

bmorg980
 3 years ago
Best ResponseYou've already chosen the best response.0so the answer is 1(x+(1/2))^2

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0no... i keep losing connection so bear with the reply timing :) what you do is solve for x.... the next step is to find the square root of both sides of the equation to clear the square on the left side... \(\huge x+\frac{1}{2}= \pm \sqrt{1}\) \(\huge x= \pm \sqrt{1}\frac{1}{2} \) \(\huge x= \pm 1\frac{1}{2} \) solve for x now :)
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