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sasogeek Group TitleBest ResponseYou've already chosen the best response.0
have you tried solving this?
 2 years ago

bmorg980 Group TitleBest ResponseYou've already chosen the best response.0
yes. initially i divided each variable by 36, but then i got a bunch of fractions and it did not make sense to me. Do i need to divide by 36?
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
ok well that's a good start :) and yes you will end up with a bunch of fractions, it happens ;) i'll tell you what to do, try that, then let me know what answer you get... are we good?
 2 years ago

bmorg980 Group TitleBest ResponseYou've already chosen the best response.0
yes! please
 2 years ago

bmorg980 Group TitleBest ResponseYou've already chosen the best response.0
ok, i got x^2+x+(1/2)^2=27/361/4
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
uhhh close, but not quite. you should've divided by 36 that way you'd have \(\large x^2+x=\frac{27}{36}\)
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
sorry for late reply, i lost connection
 2 years ago

bmorg980 Group TitleBest ResponseYou've already chosen the best response.0
ok, im going to try that. no problem, im doing some other problems while i wait
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
then with the next step, you'd get \(\large x^2+x+\frac{1}{4}=\frac{27}{36}+\frac{1}{4} \)
 2 years ago

bmorg980 Group TitleBest ResponseYou've already chosen the best response.0
ok, i have x^2+x+1/4=1/2
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
\(\large \frac{27}{36}+\frac{1}{4}= what? \)
 2 years ago

bmorg980 Group TitleBest ResponseYou've already chosen the best response.0
oops, i subtracted instead of adding. so 1?
 2 years ago

bmorg980 Group TitleBest ResponseYou've already chosen the best response.0
ok, now im a little confused, isnt it (x+b/2)^2. i dont know where to go from here
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
ok so you have \(\huge x^2+x+\frac{1}{4}=1 \) what you said is right, b=1, hence the next step is \(\huge (x+\frac{1}{2})^2=1\) :)
 2 years ago

bmorg980 Group TitleBest ResponseYou've already chosen the best response.0
so the answer is 1(x+(1/2))^2
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
no... i keep losing connection so bear with the reply timing :) what you do is solve for x.... the next step is to find the square root of both sides of the equation to clear the square on the left side... \(\huge x+\frac{1}{2}= \pm \sqrt{1}\) \(\huge x= \pm \sqrt{1}\frac{1}{2} \) \(\huge x= \pm 1\frac{1}{2} \) solve for x now :)
 2 years ago
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