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lilMissMindset

  • 2 years ago

urgent please! how do i determine the value of the coefficients of this? 2Ae^x + B + Cx = 5e^x -162x

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  1. asherwood3
    • 2 years ago
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    Remember Coefficients are the numbers in front of your variables. Variables are x , y, m , d... etc... letters. So the value of the coefficients will be the number in front of your variables... right?

  2. AnimalAin
    • 2 years ago
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    You match the coefficients with the corresponding terms. The e^x terms on both sides of the equation have to be the same, so A=5/2. Similarly, C=-162 and B=0.

  3. lilMissMindset
    • 2 years ago
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    i need a value of A, B and C

  4. AnimalAin
    • 2 years ago
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    Do you understand my explanation?

  5. lilMissMindset
    • 2 years ago
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    how did they match?

  6. AnimalAin
    • 2 years ago
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    On the LHS, there are three terms, the e^x term, the x term, and a constant term. On the right hand side, there are two, just the e^x term and the x term. If the LHS=RHS, the corresponding terms have to be equal. That means 2A=5, and C=-162. Since there is no constant term on the RHS, B=0.

  7. lilMissMindset
    • 2 years ago
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    why is it that the answer on my book is C=-18 and A=1/2

  8. AnimalAin
    • 2 years ago
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    I have no idea. I know that my answer solves the question you stated at the top.

  9. lilMissMindset
    • 2 years ago
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    i'll just figure it out. thanks a lot. :) can you answer another question? please.

  10. AnimalAin
    • 2 years ago
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    This has to do with the linear independence of the functions. You can't state a linear function in terms of a constant or an exponential, or visa-versa. So the exponential part has to match the exponential part on the other side, the linear part has to match the linear part on the other side, and the constant part has to match the constant part on the other side.

  11. AnimalAin
    • 2 years ago
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    Sure, ask away.

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