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ilovenyc

  • 2 years ago

Let A = {red, blue} and let B = {3, 4, 5}. Find A X B. A) {red, blue, 3, 4, 5} B) {(red, 3), (red, 4), (red, 5), (blue, 3), (blue, 4), (blue, 5)} C) { } D) {red, blue}

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  1. theEric
    • 2 years ago
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    Relations aren't that hard to get, actually! I suppose you know that all the elements of \[A \times B\] are coordinate pairs, such as \[(a,b)\]. Specifically, \[a\] is an element in \[A\]. I mean, \[a \in A\]. And \[b\] is an element in \[B\]. I mean, \[b \in B\]. When you try to find \[A \times B\] you want to create all the ordered pairs that exist, as long as they satisify what I just said, where\[a \in A\]and\[b\in B\]

  2. theEric
    • 2 years ago
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    So pick any element in A.

  3. ilovenyc
    • 2 years ago
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    @theEric so the answer is A

  4. theEric
    • 2 years ago
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    Not quite! When you think of \[AxB\], you have to think a coordinate pair like \[(somethingFromA, somethingFromB)\]

  5. theEric
    • 2 years ago
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    I meant \[A \times B\], sorry!

  6. theEric
    • 2 years ago
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    Pick any element in A.

  7. theEric
    • 2 years ago
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    Actually, for this multiple choice question, all you need to know is that \[A \times B\] has elements and they are coordinate pairs...

  8. ilovenyc
    • 2 years ago
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    @theEric so then whats the answer

  9. theEric
    • 2 years ago
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    I want you to understand it.

  10. theEric
    • 2 years ago
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    I'm imposing my view upon you, I know.. But understanding things like this will be essential to understanding things later.

  11. theEric
    • 2 years ago
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    I'm willing to walk you through a similar problem.

  12. theEric
    • 2 years ago
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    :)

  13. theEric
    • 2 years ago
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    \[(a \in A, b \in B)\] Example:\[(red,3)\]

  14. ilovenyc
    • 2 years ago
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    @theEric okay I did the work, and I came up with B, am i right?

  15. theEric
    • 2 years ago
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    \[red \in A\]and\[3 \in B\]so \[(red,3)\]is one of those ordered pairs in \[A \times B\].

  16. theEric
    • 2 years ago
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    If you understand that last thing I said, you'll know whether you have the answer or not! If you understand "relations" you'll know what set would have to be the relation. Would you like a hand with anything?

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