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anonymous
 4 years ago
2C + 3B +6Cx+2A+2Bx+2Cx^2=12x^2
need to determine A, B, C
anonymous
 4 years ago
2C + 3B +6Cx+2A+2Bx+2Cx^2=12x^2 need to determine A, B, C

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0We do it the same way. Let me work for a second here...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[2C + 3B +6Cx+2A+2Bx+2Cx^2=12x^2 \implies\]\[(2A+2C + 3B) +(6C+2B)x+2Cx^2=12x^2 \implies\]\[2C=12 \implies C=6\]\[6C+2B=0 \implies B=18\]\[2A+2C + 3B=0 \implies A=9\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The corresponding terms on the left and right sides of the equation have to be the same. So, we match the x^2 coefficients to get C=6, then the x coefficients (note there is none on the RHS, so the LHS has to be zero) to get B=18, then follow the same pattern to get A=9.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hey, check A, i think it's 21.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0really, i'm getting it now, thanks a lot.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think it's nine.... 3*62*18=18 implies that A has to be pretty close to nine.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you interchanged the value of A and B.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OOPs!! Hate it when that happens!! Bad substitution!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i noticed as well. it's alright! :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You seem to have it now.... even if my arithmetic is lacking. LOL Do math every day.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you're still one great teacher! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sure, i'll do a lot of math everyday. ammm, do you do some DE's?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A little. What do you have in mind?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i'll post it on a new one, so that i can give you another medal.
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