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Sir_Rico_of_Eureka Group TitleBest ResponseYou've already chosen the best response.0
same way as with an equals sign. just leave that alligator mouth there. you need to clear the fractions. try multiplying both sides by the fractions denominator
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
okay so i multiply by x on both sides 1>x so why when i have dw:1350339428053:dw why when i have this do i multiply by (x2)² @Sir_Rico_of_Eureka
 2 years ago

Sir_Rico_of_Eureka Group TitleBest ResponseYou've already chosen the best response.0
You just multiply both sides again to clear the fractions. this time however you have one more step. get x by itself
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
on the question i wrote on the picture, i must multiply by (x2)² not x2 i want to know why?
 2 years ago

Sir_Rico_of_Eureka Group TitleBest ResponseYou've already chosen the best response.0
Who said you have to multiply (x2)^2. Whats the original problem
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
the book because apparently i will lose a solution if i dont
 2 years ago

Sir_Rico_of_Eureka Group TitleBest ResponseYou've already chosen the best response.0
Whats the original problem
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
dw:1350339676275:dw
 2 years ago

Sir_Rico_of_Eureka Group TitleBest ResponseYou've already chosen the best response.0
And your book says the solution needs to multiply both sides by (x2)^2? in the back of the book?
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
yes because if i only multiply by x2 i lose a solution i dont see how
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
@TuringTest
 2 years ago

Sir_Rico_of_Eureka Group TitleBest ResponseYou've already chosen the best response.0
Hm, If you do the math the same answer comes out. Does it give you an answer to the problem
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
dw:1350340054622:dw
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
you have to keep in mind that x2 could be negative, so you need to consider cases
 2 years ago

Sir_Rico_of_Eureka Group TitleBest ResponseYou've already chosen the best response.0
I see now, if you look closely simply solving they way we did it at first is saying that x<3 and it can't be a negative number because a negative is never bigger than a positive. Therefore at some number x<3 stops being completly true. How i figured it out is plugged in 2 and saw that it equals 1/0 and you cant divide by zero. Therefore it must be a number between two and three. Thats the logical explanation. But I guess I don't know the specific rules taught in your book.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
if x2<0 the sign of the inequality would change upon multiplication, but (x2)^2 can never be negative, so that we can use without changing the sign of the inequality
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
thank you very much people!
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
welcome!
 2 years ago
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