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Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.0same way as with an equals sign. just leave that alligator mouth there. you need to clear the fractions. try multiplying both sides by the fractions denominator

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0okay so i multiply by x on both sides 1>x so why when i have dw:1350339428053:dw why when i have this do i multiply by (x2)² @Sir_Rico_of_Eureka

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.0You just multiply both sides again to clear the fractions. this time however you have one more step. get x by itself

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0on the question i wrote on the picture, i must multiply by (x2)² not x2 i want to know why?

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.0Who said you have to multiply (x2)^2. Whats the original problem

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0the book because apparently i will lose a solution if i dont

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.0Whats the original problem

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.0And your book says the solution needs to multiply both sides by (x2)^2? in the back of the book?

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0yes because if i only multiply by x2 i lose a solution i dont see how

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.0Hm, If you do the math the same answer comes out. Does it give you an answer to the problem

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1you have to keep in mind that x2 could be negative, so you need to consider cases

Sir_Rico_of_Eureka
 2 years ago
Best ResponseYou've already chosen the best response.0I see now, if you look closely simply solving they way we did it at first is saying that x<3 and it can't be a negative number because a negative is never bigger than a positive. Therefore at some number x<3 stops being completly true. How i figured it out is plugged in 2 and saw that it equals 1/0 and you cant divide by zero. Therefore it must be a number between two and three. Thats the logical explanation. But I guess I don't know the specific rules taught in your book.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1if x2<0 the sign of the inequality would change upon multiplication, but (x2)^2 can never be negative, so that we can use without changing the sign of the inequality

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0thank you very much people!
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