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Gabylovesyou
Group Title
Let A = {circle, square} and let B = {3, 4, 5}. Find A X B.
{circle, square, 3, 4, 5}
{ }
{3, 4, 5}
{(circle, 3), (circle, 4), (circle, 5), (square, 3), (square, 4), (square, 5)}
Question 21 (Multiple Choice Worth 1 points)
[3.06]
If f(x) = x^2  1, find f(3).
5
2
8
2
 one year ago
 one year ago
Gabylovesyou Group Title
Let A = {circle, square} and let B = {3, 4, 5}. Find A X B. {circle, square, 3, 4, 5} { } {3, 4, 5} {(circle, 3), (circle, 4), (circle, 5), (square, 3), (square, 4), (square, 5)} Question 21 (Multiple Choice Worth 1 points) [3.06] If f(x) = x^2  1, find f(3). 5 2 8 2
 one year ago
 one year ago

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Gabylovesyou Group TitleBest ResponseYou've already chosen the best response.0
@AccessDenied @baldymcgee6
 one year ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.2
1) A x B means the set of all ordered pairs whose first entry is an eement of A and second is an element of B. So, you'll have a set looking something like \(\{(a_1, b_2), \ (a_2, b_2)\}\) etc.
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
f(x) = x^2  1, find f(3) f(3) = (3)^2 1 f(3) = 91 f(3) = 8
 one year ago

Gabylovesyou Group TitleBest ResponseYou've already chosen the best response.0
for the first one is it A?
 one year ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.2
No, A) would simply be the union of the sets. This is represented as "A u B." A x B will have ordered pairs as elements of the set, rather than single items from each set.
 one year ago

Gabylovesyou Group TitleBest ResponseYou've already chosen the best response.0
it has to be B or C right?
 one year ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.2
It would be D): {(circle, 3), (circle, 4), (circle, 5), (square, 3), (square, 4), (square, 5)} You can see the ordered pairs: (circle, 3), (circle, 4), etc. consist of one element from A first, and then one element from B second. Basically, A x B is like the set of all combinations of elements from A and B. Would that make sense?
 one year ago
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