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Gabylovesyou
 4 years ago
Let A = {circle, square} and let B = {3, 4, 5}. Find A X B.
{circle, square, 3, 4, 5}
{ }
{3, 4, 5}
{(circle, 3), (circle, 4), (circle, 5), (square, 3), (square, 4), (square, 5)}
Question 21 (Multiple Choice Worth 1 points)
[3.06]
If f(x) = x^2  1, find f(3).
5
2
8
2
Gabylovesyou
 4 years ago
Let A = {circle, square} and let B = {3, 4, 5}. Find A X B. {circle, square, 3, 4, 5} { } {3, 4, 5} {(circle, 3), (circle, 4), (circle, 5), (square, 3), (square, 4), (square, 5)} Question 21 (Multiple Choice Worth 1 points) [3.06] If f(x) = x^2  1, find f(3). 5 2 8 2

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Gabylovesyou
 4 years ago
Best ResponseYou've already chosen the best response.0@AccessDenied @baldymcgee6

AccessDenied
 4 years ago
Best ResponseYou've already chosen the best response.21) A x B means the set of all ordered pairs whose first entry is an eement of A and second is an element of B. So, you'll have a set looking something like \(\{(a_1, b_2), \ (a_2, b_2)\}\) etc.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0f(x) = x^2  1, find f(3) f(3) = (3)^2 1 f(3) = 91 f(3) = 8

Gabylovesyou
 4 years ago
Best ResponseYou've already chosen the best response.0for the first one is it A?

AccessDenied
 4 years ago
Best ResponseYou've already chosen the best response.2No, A) would simply be the union of the sets. This is represented as "A u B." A x B will have ordered pairs as elements of the set, rather than single items from each set.

Gabylovesyou
 4 years ago
Best ResponseYou've already chosen the best response.0it has to be B or C right?

AccessDenied
 4 years ago
Best ResponseYou've already chosen the best response.2It would be D): {(circle, 3), (circle, 4), (circle, 5), (square, 3), (square, 4), (square, 5)} You can see the ordered pairs: (circle, 3), (circle, 4), etc. consist of one element from A first, and then one element from B second. Basically, A x B is like the set of all combinations of elements from A and B. Would that make sense?
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