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rebecca1233
 3 years ago
Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.
4x + 4y = 6
x + 4y = 12
4x + 4y = –12
x – 4y = –6
rebecca1233
 3 years ago
Write the equation of the line that passes through (2, 2) and (6, 3) in standard form. 4x + 4y = 6 x + 4y = 12 4x + 4y = –12 x – 4y = –6

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Sir_Rico_of_Eureka
 3 years ago
Best ResponseYou've already chosen the best response.0y=mx+b. First find slope of both those points and that = m. plug in one of those points to find the value for b. once you have a complete y=mx+b equation you can then move x and y values to one side and make it standard form.

vivalakoda
 3 years ago
Best ResponseYou've already chosen the best response.1Let (2, 2) and (6, 3) be (x1,y1) & (x2,y2) First find the slope m=(y2y1)/(x2x1) m=1/4 Then take any point (2, 2) or (6, 3) (yy1)=m(xx1) Then substitute the values of m & x1&y1 x4y+6=0

rebecca1233
 3 years ago
Best ResponseYou've already chosen the best response.0so which one is that the last option ?
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