At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

can you explain how you find the partial derivative with respect to x? Short sentance...

you basically do derivative just with respect to x and treating y as a constant

like 3x^2y+2 fx=6xy and Fy is 3x^2

right. So what is confusing you about this problem?

would Hx be 0?

no. What is the regular derivative of f(x) = e^x?

same

Think of the equation as Ce^x when taking the partial WRT x. Maybe that will help :)

but don't you have to take a derivative of the (y^2+1) with respect to x?

no, thats just a constant attached to e^x :d

so the derivative with respect to x will be the same as the given problem

ya :) good

ooo I get it

with respect to Y would it be 2ye^x?

(y^2 + 1)e^x = y^2 e^x + e^x
Hy = 2y e^x + 0
Yes, very good ^^