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anonymous
 4 years ago
find partial derivative Hx and Hy of H(x,y)=(y^2+1)e^x
anonymous
 4 years ago
find partial derivative Hx and Hy of H(x,y)=(y^2+1)e^x

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cruffo
 4 years ago
Best ResponseYou've already chosen the best response.1can you explain how you find the partial derivative with respect to x? Short sentance...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you basically do derivative just with respect to x and treating y as a constant

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1So Mproof, Hmm If you take partials, you'll be treating the OTHER variable as a constant, meaning you won't have the product rule as it might seem at first glance. Does that help? :O

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like 3x^2y+2 fx=6xy and Fy is 3x^2

cruffo
 4 years ago
Best ResponseYou've already chosen the best response.1right. So what is confusing you about this problem?

cruffo
 4 years ago
Best ResponseYou've already chosen the best response.1no. What is the regular derivative of f(x) = e^x?

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1Think of the equation as Ce^x when taking the partial WRT x. Maybe that will help :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but don't you have to take a derivative of the (y^2+1) with respect to x?

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1no, thats just a constant attached to e^x :d

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1Maybe one thing you can do to convince yourself is, distribute the e^x to each term in the brackets. Then think about what you have :o

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the derivative with respect to x will be the same as the given problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0with respect to Y would it be 2ye^x?

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1(y^2 + 1)e^x = y^2 e^x + e^x Hy = 2y e^x + 0 Yes, very good ^^
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