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math_proof
Group Title
find partial derivative Hx and Hy of H(x,y)=(y^2+1)e^x
 one year ago
 one year ago
math_proof Group Title
find partial derivative Hx and Hy of H(x,y)=(y^2+1)e^x
 one year ago
 one year ago

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cruffo Group TitleBest ResponseYou've already chosen the best response.1
can you explain how you find the partial derivative with respect to x? Short sentance...
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.1
you basically do derivative just with respect to x and treating y as a constant
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
So Mproof, Hmm If you take partials, you'll be treating the OTHER variable as a constant, meaning you won't have the product rule as it might seem at first glance. Does that help? :O
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.1
like 3x^2y+2 fx=6xy and Fy is 3x^2
 one year ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
right. So what is confusing you about this problem?
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.1
would Hx be 0?
 one year ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
no. What is the regular derivative of f(x) = e^x?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Think of the equation as Ce^x when taking the partial WRT x. Maybe that will help :)
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.1
but don't you have to take a derivative of the (y^2+1) with respect to x?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
no, thats just a constant attached to e^x :d
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Maybe one thing you can do to convince yourself is, distribute the e^x to each term in the brackets. Then think about what you have :o
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.1
so the derivative with respect to x will be the same as the given problem
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
ya :) good
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.1
ooo I get it
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.1
with respect to Y would it be 2ye^x?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
(y^2 + 1)e^x = y^2 e^x + e^x Hy = 2y e^x + 0 Yes, very good ^^
 one year ago
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