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math_proof Group Title

find partial derivative Hx and Hy of H(x,y)=(y^2+1)e^x

  • 2 years ago
  • 2 years ago

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  1. cruffo Group Title
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    can you explain how you find the partial derivative with respect to x? Short sentance...

    • 2 years ago
  2. math_proof Group Title
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    you basically do derivative just with respect to x and treating y as a constant

    • 2 years ago
  3. zepdrix Group Title
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    So Mproof, Hmm If you take partials, you'll be treating the OTHER variable as a constant, meaning you won't have the product rule as it might seem at first glance. Does that help? :O

    • 2 years ago
  4. math_proof Group Title
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    like 3x^2y+2 fx=6xy and Fy is 3x^2

    • 2 years ago
  5. cruffo Group Title
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    right. So what is confusing you about this problem?

    • 2 years ago
  6. math_proof Group Title
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    would Hx be 0?

    • 2 years ago
  7. cruffo Group Title
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    no. What is the regular derivative of f(x) = e^x?

    • 2 years ago
  8. math_proof Group Title
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    same

    • 2 years ago
  9. zepdrix Group Title
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    Think of the equation as Ce^x when taking the partial WRT x. Maybe that will help :)

    • 2 years ago
  10. math_proof Group Title
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    but don't you have to take a derivative of the (y^2+1) with respect to x?

    • 2 years ago
  11. zepdrix Group Title
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    no, thats just a constant attached to e^x :d

    • 2 years ago
  12. zepdrix Group Title
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    Maybe one thing you can do to convince yourself is, distribute the e^x to each term in the brackets. Then think about what you have :o

    • 2 years ago
  13. math_proof Group Title
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    so the derivative with respect to x will be the same as the given problem

    • 2 years ago
  14. zepdrix Group Title
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    ya :) good

    • 2 years ago
  15. math_proof Group Title
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    ooo I get it

    • 2 years ago
  16. math_proof Group Title
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    with respect to Y would it be 2ye^x?

    • 2 years ago
  17. zepdrix Group Title
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    (y^2 + 1)e^x = y^2 e^x + e^x Hy = 2y e^x + 0 Yes, very good ^^

    • 2 years ago
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