math_proof
find partial derivative Hx and Hy of H(x,y)=(y^2+1)e^x
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cruffo
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can you explain how you find the partial derivative with respect to x? Short sentance...
math_proof
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you basically do derivative just with respect to x and treating y as a constant
zepdrix
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So Mproof, Hmm If you take partials, you'll be treating the OTHER variable as a constant, meaning you won't have the product rule as it might seem at first glance.
Does that help? :O
math_proof
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like 3x^2y+2 fx=6xy and Fy is 3x^2
cruffo
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right. So what is confusing you about this problem?
math_proof
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would Hx be 0?
cruffo
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no. What is the regular derivative of f(x) = e^x?
math_proof
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same
zepdrix
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Think of the equation as Ce^x when taking the partial WRT x. Maybe that will help :)
math_proof
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but don't you have to take a derivative of the (y^2+1) with respect to x?
zepdrix
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no, thats just a constant attached to e^x :d
zepdrix
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Maybe one thing you can do to convince yourself is, distribute the e^x to each term in the brackets.
Then think about what you have :o
math_proof
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so the derivative with respect to x will be the same as the given problem
zepdrix
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ya :) good
math_proof
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ooo I get it
math_proof
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with respect to Y would it be 2ye^x?
zepdrix
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(y^2 + 1)e^x = y^2 e^x + e^x
Hy = 2y e^x + 0
Yes, very good ^^