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burhan101 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ [1(1+3h+3h^2+3h^3)](2) }{ h }\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
precalculus? or no?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
yes it is
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you should do 1  (1 + 3h + 3h^2 + 3h^3) first
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
do i just get rid of the first round bracket?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
@lgbasallote
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
correct. Distribute the  through [1 1*( everything inside parenthesis) ]
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
oh so you mutiply everything by 1 ?:S
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
sorry had to step away..
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
it's alright :P
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
correct: \[\frac{ [1(1+3h+3h^2+3h^3)](2) }{ h } = \frac{ [113h3h^23h^3]2 }{ h }\]
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
but I'm curious: did you originally have to do 1(1+h)^3 in the top?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
well i have this equation: \[y=1x^3\] and i need to find the average slope of the line passig through A (1,2) and Δx=h
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
so that was what i came up with
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
I think before you go any further, there is something that need to be corrected.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
ohh what ?
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
Here x = 1, so you want \[f(1+h) = 1(1+h)^3 = 1[(1)^3 + 3(1)^2h + 3(1)h^2 + h^3\] \[ = 1(1+3h3h^2+h^3)\] So the top would be \[\frac{ [1(1+3h3h^2+h^3)](2) }{ h } = \frac{ [1+13h+3h^2h^3]2 }{ h }\]
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
then the 2 would cancel out with 2
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
and we would factor out the h ?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
so m= \[3+3hh^2\]
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
oh wrong signs
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
hah. right. those pesky negatives...
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
but my text book says the final answer is: \[h2+3h3\] :S :S
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
just rearrange the terms in decending order in h
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
ohh it's the same thing .. :$ LOL i thought it was different haha :$
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
thankyou so much :D !
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
if part b says to calculate slope for h= 10,2,1,1/2 do i find the limits for his @cruffo ?
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
Sorry for the delay.
 2 years ago

cruffo Group TitleBest ResponseYou've already chosen the best response.1
Should just be able to plug in the numbers for h in you previous answer, \[\large h^2 + 3h  3\]
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.1
thanks :D
 2 years ago
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