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burhan101

  • 2 years ago

Simplify this :

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  1. burhan101
    • 2 years ago
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    \[\frac{ [1-(1+3h+3h^2+3h^3)]-(2) }{ h }\]

  2. lgbasallote
    • 2 years ago
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    precalculus? or no?

  3. burhan101
    • 2 years ago
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    yes it is

  4. lgbasallote
    • 2 years ago
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    you should do 1 - (1 + 3h + 3h^2 + 3h^3) first

  5. burhan101
    • 2 years ago
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    ohh okay

  6. burhan101
    • 2 years ago
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    do i just get rid of the first round bracket?

  7. burhan101
    • 2 years ago
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    @lgbasallote

  8. cruffo
    • 2 years ago
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    correct. Distribute the - through [1 -1*( everything inside parenthesis) ]

  9. burhan101
    • 2 years ago
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    oh so you mutiply everything by -1 ?:S

  10. burhan101
    • 2 years ago
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    @cruffo

  11. cruffo
    • 2 years ago
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    sorry had to step away..

  12. burhan101
    • 2 years ago
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    it's alright :P

  13. cruffo
    • 2 years ago
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    correct: \[\frac{ [1-(1+3h+3h^2+3h^3)]-(2) }{ h } = \frac{ [1-1-3h-3h^2-3h^3]-2 }{ h }\]

  14. cruffo
    • 2 years ago
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    but I'm curious: did you originally have to do 1-(1+h)^3 in the top?

  15. burhan101
    • 2 years ago
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    well i have this equation: \[y=1-x^3\] and i need to find the average slope of the line passig through A (-1,2) and Δx=h

  16. burhan101
    • 2 years ago
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    so that was what i came up with

  17. cruffo
    • 2 years ago
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    I think before you go any further, there is something that need to be corrected.

  18. burhan101
    • 2 years ago
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    ohh what ?

  19. cruffo
    • 2 years ago
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    Here x = -1, so you want \[f(-1+h) = 1-(-1+h)^3 = 1-[(-1)^3 + 3(-1)^2h + 3(-1)h^2 + h^3\] \[ = 1-(-1+3h-3h^2+h^3)\] So the top would be \[\frac{ [1-(-1+3h-3h^2+h^3)]-(2) }{ h } = \frac{ [1+1-3h+3h^2-h^3]-2 }{ h }\]

  20. burhan101
    • 2 years ago
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    then the -2 would cancel out with 2

  21. burhan101
    • 2 years ago
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    and we would factor out the h ?

  22. cruffo
    • 2 years ago
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    you got it.

  23. burhan101
    • 2 years ago
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    so m= \[3+3h-h^2\]

  24. cruffo
    • 2 years ago
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    yep.

  25. burhan101
    • 2 years ago
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    oh wrong signs

  26. cruffo
    • 2 years ago
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    hah. right. those pesky negatives...

  27. burhan101
    • 2 years ago
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    but my text book says the final answer is: \[-h2+3h-3\] :S :S

  28. cruffo
    • 2 years ago
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    just rearrange the terms in decending order in h

  29. burhan101
    • 2 years ago
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    ohh it's the same thing .. :$ LOL i thought it was different haha :$

  30. burhan101
    • 2 years ago
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    thank-you so much :D !

  31. cruffo
    • 2 years ago
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    np!

  32. burhan101
    • 2 years ago
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    if part b says to calculate slope for h= 10,2,1,1/2 do i find the limits for his @cruffo ?

  33. cruffo
    • 2 years ago
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    Sorry for the delay.

  34. cruffo
    • 2 years ago
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    Should just be able to plug in the numbers for h in you previous answer, \[\large -h^2 + 3h - 3\]

  35. burhan101
    • 2 years ago
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    thanks :D

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