anonymous
  • anonymous
Simplify this :
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\frac{ [1-(1+3h+3h^2+3h^3)]-(2) }{ h }\]
lgbasallote
  • lgbasallote
precalculus? or no?
anonymous
  • anonymous
yes it is

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lgbasallote
  • lgbasallote
you should do 1 - (1 + 3h + 3h^2 + 3h^3) first
anonymous
  • anonymous
ohh okay
anonymous
  • anonymous
do i just get rid of the first round bracket?
anonymous
  • anonymous
@lgbasallote
cruffo
  • cruffo
correct. Distribute the - through [1 -1*( everything inside parenthesis) ]
anonymous
  • anonymous
oh so you mutiply everything by -1 ?:S
anonymous
  • anonymous
@cruffo
cruffo
  • cruffo
sorry had to step away..
anonymous
  • anonymous
it's alright :P
cruffo
  • cruffo
correct: \[\frac{ [1-(1+3h+3h^2+3h^3)]-(2) }{ h } = \frac{ [1-1-3h-3h^2-3h^3]-2 }{ h }\]
cruffo
  • cruffo
but I'm curious: did you originally have to do 1-(1+h)^3 in the top?
anonymous
  • anonymous
well i have this equation: \[y=1-x^3\] and i need to find the average slope of the line passig through A (-1,2) and Δx=h
anonymous
  • anonymous
so that was what i came up with
cruffo
  • cruffo
I think before you go any further, there is something that need to be corrected.
anonymous
  • anonymous
ohh what ?
cruffo
  • cruffo
Here x = -1, so you want \[f(-1+h) = 1-(-1+h)^3 = 1-[(-1)^3 + 3(-1)^2h + 3(-1)h^2 + h^3\] \[ = 1-(-1+3h-3h^2+h^3)\] So the top would be \[\frac{ [1-(-1+3h-3h^2+h^3)]-(2) }{ h } = \frac{ [1+1-3h+3h^2-h^3]-2 }{ h }\]
anonymous
  • anonymous
then the -2 would cancel out with 2
anonymous
  • anonymous
and we would factor out the h ?
cruffo
  • cruffo
you got it.
anonymous
  • anonymous
so m= \[3+3h-h^2\]
cruffo
  • cruffo
yep.
anonymous
  • anonymous
oh wrong signs
cruffo
  • cruffo
hah. right. those pesky negatives...
anonymous
  • anonymous
but my text book says the final answer is: \[-h2+3h-3\] :S :S
cruffo
  • cruffo
just rearrange the terms in decending order in h
anonymous
  • anonymous
ohh it's the same thing .. :$ LOL i thought it was different haha :$
anonymous
  • anonymous
thank-you so much :D !
cruffo
  • cruffo
np!
anonymous
  • anonymous
if part b says to calculate slope for h= 10,2,1,1/2 do i find the limits for his @cruffo ?
cruffo
  • cruffo
Sorry for the delay.
cruffo
  • cruffo
Should just be able to plug in the numbers for h in you previous answer, \[\large -h^2 + 3h - 3\]
anonymous
  • anonymous
thanks :D

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