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find derivative of g(x)=2tan^3 (4piex)

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what have you got so far?
i replaced the 4piex to u
oh yeah. sorry i forgot this part of derivatives.

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Other answers:

try replacing tan(4 pi x) with u so you have 2(u)^3 then use the chain rule from there
ok i got: 1/2 x^2{(16-x^2)^-1/2(2x)}+(16-x^2)^-1/2 (x)
can you show me the steps you took to get that?
i did the product rule and chain
you dont have to use the product rule here
the first step is to differentiate 2(u)^3 with respect to u
ok i get that
what do you get?
1/2 x^2 (u)^1/2
to differentiate 2(u)^3 with respect to u, you just need to use the power rule so it becomes 6u^2
oops i did the wrong prob!!
oh so what is the problem you need to solve?
that same prob but i did the wrong work
ok so can you differentiate 2u^3?

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