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jeffrey_beltran

  • 3 years ago

find derivative of g(x)=2tan^3 (4piex)

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  1. franciscanmonk
    • 3 years ago
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    what have you got so far?

  2. jeffrey_beltran
    • 3 years ago
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    i replaced the 4piex to u

  3. franciscanmonk
    • 3 years ago
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    oh yeah. sorry i forgot this part of derivatives.

  4. tjones89
    • 3 years ago
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    try replacing tan(4 pi x) with u so you have 2(u)^3 then use the chain rule from there

  5. jeffrey_beltran
    • 3 years ago
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    ok i got: 1/2 x^2{(16-x^2)^-1/2(2x)}+(16-x^2)^-1/2 (x)

  6. tjones89
    • 3 years ago
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    can you show me the steps you took to get that?

  7. jeffrey_beltran
    • 3 years ago
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    i did the product rule and chain

  8. tjones89
    • 3 years ago
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    you dont have to use the product rule here

  9. tjones89
    • 3 years ago
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    the first step is to differentiate 2(u)^3 with respect to u

  10. jeffrey_beltran
    • 3 years ago
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    ok i get that

  11. tjones89
    • 3 years ago
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    what do you get?

  12. jeffrey_beltran
    • 3 years ago
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    1/2 x^2 (u)^1/2

  13. tjones89
    • 3 years ago
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    to differentiate 2(u)^3 with respect to u, you just need to use the power rule so it becomes 6u^2

  14. jeffrey_beltran
    • 3 years ago
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    oops i did the wrong prob!!

  15. tjones89
    • 3 years ago
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    oh so what is the problem you need to solve?

  16. jeffrey_beltran
    • 3 years ago
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    that same prob but i did the wrong work

  17. tjones89
    • 3 years ago
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    ok so can you differentiate 2u^3?

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