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lgbasallote
Group Title
Given:
\[A = \{x: 1 \le x \le 5\}\]
why is \[A' = \{x : x < 1 \vee x > 5\}\]
and not \[A' = \{x: x< 1 \wedge x > 5\}\]
 2 years ago
 2 years ago
lgbasallote Group Title
Given: \[A = \{x: 1 \le x \le 5\}\] why is \[A' = \{x : x < 1 \vee x > 5\}\] and not \[A' = \{x: x< 1 \wedge x > 5\}\]
 2 years ago
 2 years ago

This Question is Closed

LolWolf Group TitleBest ResponseYou've already chosen the best response.2
Since \(x\) cannot be both less than one and greater than five at one time (otherwise we have a logical contradiction). Also, De Morgan's laws are useful for this.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so does that mean \[A = \{x : x \ge 1 \wedge x \le 5\}\]
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.2
In any case: \[ A=\{x1\leq x\leq 5\}=\{x1\leq x \wedge x\leq 5\} \]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i can't believe i didn't think of that first reason....
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
Unless your x's can quantum tunnel . . .
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
uhoh....math conversation.....time to leave..
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
(Sorry, I've been hanging out in the Physics section too long)
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.2
Go go, quantum entanglement and random transmission of data!
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
Strange things can happen in this here multiverse.
 2 years ago
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