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synergy87

  • 2 years ago

Need help explaining this question in words about complex conjugates (pre-cal). Thank you in advance. http://imageshack.us/a/img833/9578/help2r.jpg

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  1. LolWolf
    • 2 years ago
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    The function given is not a polynomial since one of the exponents is \(\not \in \mathbb{N_0}\), and it is not defined for all \(x\in \mathbb{C}\), so the Conjugate Zero Theorem does not apply.

  2. synergy87
    • 2 years ago
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    Thanks that worked, anyway you could give me a brief description of how I'd solve the problem? was trying to get that last problem turned in before due date...so my friend helped me with it. I'd like to know how to have solved it myself.

  3. synergy87
    • 2 years ago
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    This one was weird, I did 10 problems prior to this one where I just found the zeros of different degree polynomials...but don't understand what it is asking for me to do with the P(7i)...etc

  4. LolWolf
    • 2 years ago
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    \(P(7i)\) is simply evaluating the function \(P\) at the point \(x=0+7i\), I guess to prove that it is, in fact, a zero, but it also says to evaluate it at \(P(-7i)\) to show that \(-7i\) (the conjugate) is not a root.

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