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Girly17 Group Title

|x + 3| < 5  (1 point) –8 < x < 2 –2 < x < 8 3 < x < 5 –3 < x < 5

  • 2 years ago
  • 2 years ago

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  1. jim_thompson5910 Group Title
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    Similar Example: |x + 1| < 7 -7 < x + 1 < 7 -7-1 < x + 1-1 < 7-1 -8 < x < 6 So the solution is -8 < x < 6

    • 2 years ago
  2. znimon Group Title
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    Think of the absolute value of x+3 as "some number" that inequality is saying some number is less than 5 units away from 0.

    • 2 years ago
  3. znimon Group Title
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    It follows then that |dw:1350359096163:dw| x+3 falls within the shaded region.

    • 2 years ago
  4. znimon Group Title
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    So what can you draw from that?

    • 2 years ago
  5. Girly17 Group Title
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    Idk

    • 2 years ago
  6. jim_thompson5910 Group Title
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    does my example help?

    • 2 years ago
  7. Girly17 Group Title
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    Nop

    • 2 years ago
  8. jim_thompson5910 Group Title
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    |x + 3| < 5 becomes -5 < x +3 < 5 Now solve for x

    • 2 years ago
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