Girly17
x + 3 < 5 (1 point)
–8 < x < 2
–2 < x < 8
3 < x < 5
–3 < x < 5



This Question is Closed

jim_thompson5910
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Similar Example:
x + 1 < 7
7 < x + 1 < 7
71 < x + 11 < 71
8 < x < 6
So the solution is 8 < x < 6

znimon
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Think of the absolute value of x+3 as "some number" that inequality is saying some number is less than 5 units away from 0.

znimon
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It follows then that dw:1350359096163:dw x+3 falls within the shaded region.

znimon
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So what can you draw from that?

Girly17
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Idk

jim_thompson5910
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does my example help?

Girly17
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Nop

jim_thompson5910
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x + 3 < 5
becomes
5 < x +3 < 5
Now solve for x