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Girly17

  • 3 years ago

|x + 3| < 5  (1 point) –8 < x < 2 –2 < x < 8 3 < x < 5 –3 < x < 5

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  1. jim_thompson5910
    • 3 years ago
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    Similar Example: |x + 1| < 7 -7 < x + 1 < 7 -7-1 < x + 1-1 < 7-1 -8 < x < 6 So the solution is -8 < x < 6

  2. znimon
    • 3 years ago
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    Think of the absolute value of x+3 as "some number" that inequality is saying some number is less than 5 units away from 0.

  3. znimon
    • 3 years ago
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    It follows then that |dw:1350359096163:dw| x+3 falls within the shaded region.

  4. znimon
    • 3 years ago
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    So what can you draw from that?

  5. Girly17
    • 3 years ago
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    Idk

  6. jim_thompson5910
    • 3 years ago
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    does my example help?

  7. Girly17
    • 3 years ago
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    Nop

  8. jim_thompson5910
    • 3 years ago
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    |x + 3| < 5 becomes -5 < x +3 < 5 Now solve for x

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