3psilon
Lim x->0 sinx/x^2+4x why is it 1/4?!
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Hero
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Hint: sin(x)/x --> 1
3psilon
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I knew it had to do with the squeeze theorem that x^2 is throwing me off
LolWolf
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We can use a simple identity to solve such:
\[\lim_{x\to0}\left(\frac{\sin x}{x^2+4x}\right)=\lim_{x\to0}\left(\frac{\sin x}{x(x+4)}\right)=\lim_{x\to0}\left(\frac{1}{x+4}\right)=\frac{1}{4}\]
3psilon
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AHhhh I see it!
LolWolf
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(Sorry, I was about to do l'Hospital's and then I saw the factorization at the bottom, @Hero !)
3psilon
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Thanks @LolWolf
Hero
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I suppose my hint was useless