3psilon
  • 3psilon
Lim x->0 sinx/x^2+4x why is it 1/4?!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Hero
  • Hero
Hint: sin(x)/x --> 1
3psilon
  • 3psilon
I knew it had to do with the squeeze theorem that x^2 is throwing me off
anonymous
  • anonymous
We can use a simple identity to solve such: \[\lim_{x\to0}\left(\frac{\sin x}{x^2+4x}\right)=\lim_{x\to0}\left(\frac{\sin x}{x(x+4)}\right)=\lim_{x\to0}\left(\frac{1}{x+4}\right)=\frac{1}{4}\]

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3psilon
  • 3psilon
AHhhh I see it!
anonymous
  • anonymous
(Sorry, I was about to do l'Hospital's and then I saw the factorization at the bottom, @Hero !)
3psilon
  • 3psilon
Thanks @LolWolf
Hero
  • Hero
I suppose my hint was useless

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