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You can try substituting y = asinx + bcosx

why would that help. I'm in diff eq as well and I wasn't thinking about that.

its called th method of undetermined coefficients

put it on the left side....compare with coeffs on the right fr etermining a a and b

isn't it
y=a cos x + b sinx + cx cos x + dx sin x

that is for a special case i think

what are the roots anyway?
+i, -i
aren't they like, twice? then it will be case 4?

r^2 - 4r +3 = 0
(r - 3)(r-1)
r= 3, 1

that is for the homo part

i did that, i always get 0 for B. it's not supposed to be the answer.

im getting the answer as b=1, a=0
which means y=cos x
y=cos x satisfies the above eqns

oh sorry. i looked at the wrong answer on my book. i am sorry. Our answer is right. Thank you!

Your welcome