A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.0guess that substn should work..

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0aaa. i think i got it. wait, i'll try.

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.0ohh wait,,i didnt see a "y" also in there. !!

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1@shubhamsrg I think it's just written in 'operator' notation... \[\frac{ d^2y }{dt^2 } +4y = 4\sin^2x\] correct @lilMissMindset ?

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.0there's a y also with D^2 .. i had got that,,i didnt see a y being multiplied to whole that time..sorry..

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ d^2y }{ dx^2 } +4y =4\sin^2x\] rather.

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1yes he's correct I believe y =a*cos^2 x

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1did you get it to work?

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1that's the particular soln. anyway...

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0isn't it like, Acosx+Bsinx+Cxcosx+Dxsinx

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0since sinx is twice? applying case 4 of undetermined coefficients

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0where it has some repeated imaginary root

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1look d^2 (a*cos^2(x)) /dx^2 +4a cos^2(x) = 4sin^2(x) second derivative of a*cos^2(x) is 2a*cos^2(x)  2a*sin^2(x)

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1this is for the particular solution...

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1finding the homogeneous solution shouldn't be a problem...

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1\[\lambda ^2 +4 =0\]

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0i'll work on it. please guide me still, in case i get stuck.

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1hold on... can you tell me what part is giving you problems?

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0getting Yp gives me a lot of trouble. since you told me that it's acos^2 x, i am differentiating it now.

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0how about if the given is cos^x, then Yp=asin^2 x?

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1if the forcing term is cos^2 x you mean?

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0i forgot 2, lol.

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1yeah, for the same equation, I believe that a*sin^2 x would be the trial solution then...

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1yes. it would. just checked it.

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0darn, i can't do it. show me a brief solution please. so i can learn how.

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0just for the Yp part. swear.

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1well, I did it already (a*cos^2(x))" +4a cos^2(x) = 4sin^2(x)

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.12a*cos^2(x)  2a*sin^2(x) +4a cos^2(x) = 4sin^2(x)

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1hmm, I see your point ...

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1I guess you'll be needing something like yp = a*cos^2(x) + b*sin^2(x)

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1let me try it out and see...

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1seems to work... I got a= 2 b=2

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1so 2cos^2 x 2sin^2 x

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0answer here in the book is 1/2(1xsin2x) for the Yp part.

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1I'll assume that's (1/2)*( 1  x*sin^2 x )

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1you should check the original, I think you might have written the problem wrong...

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1you left out and x I think...

lilMissMindset
 2 years ago
Best ResponseYou've already chosen the best response.0i don't think so.

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1(1/2)*( sin^2 x  x*sin 2x ) ??

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1I don't see how (1/2)(1xsin2x) can work... maybe I'm missing something.

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1something's off in your original equation or that soln.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.