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polygon of n sides have how many diagonals ?

[n(n-3)]/2 ... is that it?

yes, so u could u form 2 equations using this formula?

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how?

take side of one polygon as x and other as y
x+y=13
[x(x-3)]/2+[y(y-3)]/2 = 25

after that?

can u work out second equation and tell me what u get as x^2+y^2= ?

got it :)) the two polygon has 5 and 8 sides

yes! that is correct.
u had options ?

by option , i meant choices.

owh.. hahaha! my bad.. none :)

then u worked it out to get 5, 8 ? nice!

yes! :)) you helped me a lot there..

so, did u get how i got this :
[x(x-3)]/2+[y(y-3)]/2 = 25
?

when sides is 'x' number of diagonals is x (x-3)/2
same for y
and total number of diagonals = 25

and once we know x^2+y^2 and x+y ,
we can find x and y
you know how to ? or need help with that ?

uhhhh help please :)

ummm is xy=40?

yes ! it is :)
xy =40 is correct.
what u got for x-y ?

see, (x-y)^2 = x^2+y^2 -2xy = 89 -2(40) = 9
so, x-y = 3

x+y = 13
x-y =3
just add them

OOOOOOOOOOOOHHHHHHHHH!!!!!!! ok thanks man VERY MUCH haha i get it now :))))

where did the xy come from? :) pls help thaaaaaaaaanks

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