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suneja

  • 3 years ago

if 10^50-74 is written as an integer in base 10 notation wat is the sum of the digits in that integer

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  1. suneja
    • 3 years ago
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    ans is 440 but how do v solve tis??

  2. Fall12-13
    • 3 years ago
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    (10^4) - 74 = ? (10^4) - 10*7.4 = ? 10*[(10^3) - 7.4] = ? 10*[10^3 - 7.4] = 992.6*10 = 9926 = 9*2+2+6 = 26 Note that 10^4 will yield two nines a six and a two. so solving for 10^50 and 74 will give 48 nines a six and a two: 10*[10^49 - 7.4] = 9*48+2+6 = 440

  3. suneja
    • 3 years ago
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    @Fall12-13 wer did u get tis frm i hav the exact soln wid me but didnt get it as in how 10^50 gives 48 nines

  4. Fall12-13
    • 3 years ago
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    Can you post your steps/how you worked the problem? We can see where you're going wrong then.

  5. suneja
    • 3 years ago
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    solve tis 10(10^49-7.4)

  6. Fall12-13
    • 3 years ago
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    You get 48 nines,but the LAST numbers are 2 and 6, we take them in and add them. 10(10^49-7.4)=99999999999999999999999999999999999999999999999926

  7. suneja
    • 3 years ago
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    got it... it was silly ques!! thanks:)

  8. Fall12-13
    • 3 years ago
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    No problem, nice to know.

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