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 2 years ago
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?
 2 years ago
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?

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hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1using the property that diagonals of regular pentagon trisect all the interior angles, we get angle OAB = OBC = 36 degrees (108/3, angle A=angle B =108 degrees) now can u find EOC ?

Asdianafghjkl
 one year ago
Best ResponseYou've already chosen the best response.0Can you explain further? Sorry I can't understand :3

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1diagonals of regular pentagon trisect all the interior angles so, angle ABO will be 1/3 times interior angle ABC so, angle ABO = 36 similarly angle BAO = 36 so angle AOB will be 180 3636 (because angle in a triangle sum upto 180) and since EOC is vertical to AOB EOC = AOB

ClaP01
 one year ago
Best ResponseYou've already chosen the best response.0how do you know that the interior angle of ABC is 108?

ClaP01
 one year ago
Best ResponseYou've already chosen the best response.0how do you find the angle A is 108 as well as the angle B? sorry I'm confused
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