A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?
anonymous
 3 years ago
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350441129403:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1using the property that diagonals of regular pentagon trisect all the interior angles, we get angle OAB = OBC = 36 degrees (108/3, angle A=angle B =108 degrees) now can u find EOC ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Can you explain further? Sorry I can't understand :3

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1diagonals of regular pentagon trisect all the interior angles so, angle ABO will be 1/3 times interior angle ABC so, angle ABO = 36 similarly angle BAO = 36 so angle AOB will be 180 3636 (because angle in a triangle sum upto 180) and since EOC is vertical to AOB EOC = AOB

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0how do you know that the interior angle of ABC is 108?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0how do you find the angle A is 108 as well as the angle B? sorry I'm confused
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.