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eroshea
 3 years ago
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?
eroshea
 3 years ago
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1using the property that diagonals of regular pentagon trisect all the interior angles, we get angle OAB = OBC = 36 degrees (108/3, angle A=angle B =108 degrees) now can u find EOC ?

Asdianafghjkl
 2 years ago
Best ResponseYou've already chosen the best response.0Can you explain further? Sorry I can't understand :3

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1diagonals of regular pentagon trisect all the interior angles so, angle ABO will be 1/3 times interior angle ABC so, angle ABO = 36 similarly angle BAO = 36 so angle AOB will be 180 3636 (because angle in a triangle sum upto 180) and since EOC is vertical to AOB EOC = AOB

ClaP01
 2 years ago
Best ResponseYou've already chosen the best response.0how do you know that the interior angle of ABC is 108?

ClaP01
 2 years ago
Best ResponseYou've already chosen the best response.0how do you find the angle A is 108 as well as the angle B? sorry I'm confused
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