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eroshea

  • 3 years ago

If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?

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  1. eroshea
    • 3 years ago
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    |dw:1350441129403:dw|

  2. hartnn
    • 3 years ago
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    using the property that diagonals of regular pentagon trisect all the interior angles, we get angle OAB = OBC = 36 degrees (108/3, angle A=angle B =108 degrees) now can u find EOC ?

  3. hartnn
    • 3 years ago
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    by first finding AOB

  4. Asdianafghjkl
    • 2 years ago
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    Can you explain further? Sorry I can't understand :3

  5. hartnn
    • 2 years ago
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    diagonals of regular pentagon trisect all the interior angles so, angle ABO will be 1/3 times interior angle ABC so, angle ABO = 36 similarly angle BAO = 36 so angle AOB will be 180 -36-36 (because angle in a triangle sum upto 180) and since EOC is vertical to AOB EOC = AOB

  6. ClaP01
    • 2 years ago
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    how do you know that the interior angle of ABC is 108?

  7. ClaP01
    • 2 years ago
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    how do you find the angle A is 108 as well as the angle B? sorry I'm confused

  8. elypab
    • one year ago
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    So EOC is 108?

  9. hartnn
    • 11 months ago
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    yes

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