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If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?
 one year ago
 one year ago
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?
 one year ago
 one year ago

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hartnnBest ResponseYou've already chosen the best response.1
using the property that diagonals of regular pentagon trisect all the interior angles, we get angle OAB = OBC = 36 degrees (108/3, angle A=angle B =108 degrees) now can u find EOC ?
 one year ago

AsdianafghjklBest ResponseYou've already chosen the best response.0
Can you explain further? Sorry I can't understand :3
 3 months ago

hartnnBest ResponseYou've already chosen the best response.1
diagonals of regular pentagon trisect all the interior angles so, angle ABO will be 1/3 times interior angle ABC so, angle ABO = 36 similarly angle BAO = 36 so angle AOB will be 180 3636 (because angle in a triangle sum upto 180) and since EOC is vertical to AOB EOC = AOB
 3 months ago

ClaP01Best ResponseYou've already chosen the best response.0
how do you know that the interior angle of ABC is 108?
 3 months ago

ClaP01Best ResponseYou've already chosen the best response.0
how do you find the angle A is 108 as well as the angle B? sorry I'm confused
 3 months ago
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