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eroshea
Group Title
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?
 one year ago
 one year ago
eroshea Group Title
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?
 one year ago
 one year ago

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eroshea Group TitleBest ResponseYou've already chosen the best response.0
dw:1350441129403:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
using the property that diagonals of regular pentagon trisect all the interior angles, we get angle OAB = OBC = 36 degrees (108/3, angle A=angle B =108 degrees) now can u find EOC ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
by first finding AOB
 one year ago

Asdianafghjkl Group TitleBest ResponseYou've already chosen the best response.0
Can you explain further? Sorry I can't understand :3
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
diagonals of regular pentagon trisect all the interior angles so, angle ABO will be 1/3 times interior angle ABC so, angle ABO = 36 similarly angle BAO = 36 so angle AOB will be 180 3636 (because angle in a triangle sum upto 180) and since EOC is vertical to AOB EOC = AOB
 8 months ago

ClaP01 Group TitleBest ResponseYou've already chosen the best response.0
how do you know that the interior angle of ABC is 108?
 8 months ago

ClaP01 Group TitleBest ResponseYou've already chosen the best response.0
how do you find the angle A is 108 as well as the angle B? sorry I'm confused
 8 months ago
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