anonymous
  • anonymous
If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
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hartnn
  • hartnn
using the property that diagonals of regular pentagon trisect all the interior angles, we get angle OAB = OBC = 36 degrees (108/3, angle A=angle B =108 degrees) now can u find EOC ?
hartnn
  • hartnn
by first finding AOB

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anonymous
  • anonymous
Can you explain further? Sorry I can't understand :3
hartnn
  • hartnn
diagonals of regular pentagon trisect all the interior angles so, angle ABO will be 1/3 times interior angle ABC so, angle ABO = 36 similarly angle BAO = 36 so angle AOB will be 180 -36-36 (because angle in a triangle sum upto 180) and since EOC is vertical to AOB EOC = AOB
anonymous
  • anonymous
how do you know that the interior angle of ABC is 108?
anonymous
  • anonymous
how do you find the angle A is 108 as well as the angle B? sorry I'm confused
anonymous
  • anonymous
So EOC is 108?
hartnn
  • hartnn
yes

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