suneja
find the sum of
(1/(2^21) +1/( 4^21)+1/(6^21)+...+1/(20^21))



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integralsabiti
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dw:1350388976936:dw

suneja
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how did u get tis

mahmit2012
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dw:1350389094272:dw

integralsabiti
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difference of squares on denominator
a^2b^2=(ab)(a+b)

suneja
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dats partial sum rite

mahmit2012
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yes

suneja
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@mahmit2012 but ans is 10/21
can u show ur steps of partial sums

Coolsector
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dw:1350390395436:dw

Coolsector
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because 2n when n = 10 is 20 .. just to do the correction for mahmit2012

suneja
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@Coolsector thanks..

mahmit2012
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oh yes uper bound is 10 .

suneja
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ya got it finally:)
thanks ppl