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suneja
 3 years ago
find the sum of
(1/(2^21) +1/( 4^21)+1/(6^21)+...+1/(20^21))
suneja
 3 years ago
find the sum of (1/(2^21) +1/( 4^21)+1/(6^21)+...+1/(20^21))

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integralsabiti
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350388976936:dw

mahmit2012
 3 years ago
Best ResponseYou've already chosen the best response.5dw:1350389094272:dw

integralsabiti
 3 years ago
Best ResponseYou've already chosen the best response.0difference of squares on denominator a^2b^2=(ab)(a+b)

suneja
 3 years ago
Best ResponseYou've already chosen the best response.0@mahmit2012 but ans is 10/21 can u show ur steps of partial sums

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1350390395436:dw

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.2because 2n when n = 10 is 20 .. just to do the correction for mahmit2012

mahmit2012
 3 years ago
Best ResponseYou've already chosen the best response.5oh yes uper bound is 10 .

suneja
 3 years ago
Best ResponseYou've already chosen the best response.0ya got it finally:) thanks ppl
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