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suneja

find the sum of (1/(2^2-1) +1/( 4^2-1)+1/(6^2-1)+...+1/(20^2-1))

  • one year ago
  • one year ago

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  1. integralsabiti
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    |dw:1350388976936:dw|

    • one year ago
  2. suneja
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    how did u get tis

    • one year ago
  3. mahmit2012
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    |dw:1350389094272:dw|

    • one year ago
  4. integralsabiti
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    difference of squares on denominator a^2-b^2=(a-b)(a+b)

    • one year ago
  5. suneja
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    dats partial sum rite

    • one year ago
  6. mahmit2012
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    yes

    • one year ago
  7. suneja
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    @mahmit2012 but ans is 10/21 can u show ur steps of partial sums

    • one year ago
  8. Coolsector
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    |dw:1350390395436:dw|

    • one year ago
  9. Coolsector
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    because 2n when n = 10 is 20 .. just to do the correction for mahmit2012

    • one year ago
  10. suneja
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    @Coolsector thanks..

    • one year ago
  11. mahmit2012
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    oh yes uper bound is 10 .

    • one year ago
  12. suneja
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    ya got it finally:) thanks ppl

    • one year ago
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