## anonymous 3 years ago (w-4)^2=2w^2-7w-4

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1. anonymous

w as in complex a+bi

2. anonymous

?

3. anonymous

It just says solve for w. Is that what you mean?

4. anonymous

okey then I guess it's not complex

5. anonymous

Well then you start by distrubuting the left term, do you know how to do that?

6. anonymous

yes? w^2-4^2?

7. anonymous

Not exactly don't forget that:$(a+b)^{2}=a^{2}+2ab+b ^{2}$

8. anonymous

$w ^{2}-8w+16 =2w ^{2}-7w-4$

9. anonymous

$-w ^{2}-w+20=0$

10. anonymous

$w ^{2}+w-20=0$

11. anonymous

$w= \frac{ 1 }{ 2 } \pm \sqrt{\frac{ 1^{2} }{ 2^{2}}+20}$

12. anonymous

$w= \frac{ 1 }{ 2 } \pm \sqrt{\frac{ 81 }{4 }} = \frac{ 1 }{ 2 } \pm \frac{ 9 }{ 2 }$

13. anonymous

The two solutions which satisfies the equation are $w _{1}=5; w _{2}=-4$

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