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samanthawooten36

  • 2 years ago

(w-4)^2=2w^2-7w-4

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  1. frx
    • 2 years ago
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    w as in complex a+bi

  2. frx
    • 2 years ago
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    ?

  3. samanthawooten36
    • 2 years ago
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    It just says solve for w. Is that what you mean?

  4. frx
    • 2 years ago
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    okey then I guess it's not complex

  5. frx
    • 2 years ago
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    Well then you start by distrubuting the left term, do you know how to do that?

  6. samanthawooten36
    • 2 years ago
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    yes? w^2-4^2?

  7. frx
    • 2 years ago
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    Not exactly don't forget that:\[(a+b)^{2}=a^{2}+2ab+b ^{2}\]

  8. frx
    • 2 years ago
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    \[w ^{2}-8w+16 =2w ^{2}-7w-4\]

  9. frx
    • 2 years ago
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    \[-w ^{2}-w+20=0\]

  10. frx
    • 2 years ago
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    \[w ^{2}+w-20=0\]

  11. frx
    • 2 years ago
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    \[w= \frac{ 1 }{ 2 } \pm \sqrt{\frac{ 1^{2} }{ 2^{2}}+20}\]

  12. frx
    • 2 years ago
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    \[w= \frac{ 1 }{ 2 } \pm \sqrt{\frac{ 81 }{4 }} = \frac{ 1 }{ 2 } \pm \frac{ 9 }{ 2 }\]

  13. frx
    • 2 years ago
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    The two solutions which satisfies the equation are \[w _{1}=5; w _{2}=-4\]

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