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anonymous
 4 years ago
(w4)^2=2w^27w4
anonymous
 4 years ago
(w4)^2=2w^27w4

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It just says solve for w. Is that what you mean?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okey then I guess it's not complex

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well then you start by distrubuting the left term, do you know how to do that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Not exactly don't forget that:\[(a+b)^{2}=a^{2}+2ab+b ^{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[w ^{2}8w+16 =2w ^{2}7w4\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[w= \frac{ 1 }{ 2 } \pm \sqrt{\frac{ 1^{2} }{ 2^{2}}+20}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[w= \frac{ 1 }{ 2 } \pm \sqrt{\frac{ 81 }{4 }} = \frac{ 1 }{ 2 } \pm \frac{ 9 }{ 2 }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The two solutions which satisfies the equation are \[w _{1}=5; w _{2}=4\]
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